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boyakko [2]
4 years ago
10

If HJ= 7x-27 . Find the value of x

Mathematics
2 answers:
Alinara [238K]4 years ago
7 0

we are given

HJ=7x-27

Since, we have to solve for x

so, we will isolate x on anyone side

step-1: Add both sides 27

HJ+27=7x-27+27

HJ+27=7x

step-2: Divide both sides by 7

HJ+27=7x

\frac{HJ+27}{7}= \frac{7x}{7}

now, we can simplify it

\frac{HJ+27}{7}= x

x=\frac{HJ+27}{7}................Answer


Norma-Jean [14]4 years ago
4 0

Answer:

The value of x is x=\frac{HJ+27}{7}}

Step-by-step explanation:

Consider the provided equation.

HJ= 7x-27

We need to solve the equation for x.

Add 27 to the both side of the equation.

HJ+27= 7x-27+27

HJ+27= 7x

Now, divide both the sides by 7.

\frac{HJ+27}{7}=\frac{7x}{7}

x=\frac{HJ+27}{7}}

Hence, the value of x is x=\frac{HJ+27}{7}}

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Answer:

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Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

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Step 2: Factor left side of equation.

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Step 3: Set factors equal to 0.

x−1=0 or x+2=0

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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