Communications in which data can be transmitted intermittently rather than in a steady stream.
Answer:
The answer is "5 users and 1 block".
Explanation:
In Option a:
Bandwidth total 
Any User Requirement 
The method for calculating the number of approved users also is:
Now, calculate the price of each person for overall bandwidth and demands,


In Option b:



mean user 

max user 

Answer:
The last 2 point in the given question is the correct answer to the given question i.e
- an argument passed to the function in the correct positional order
- an argument wherein the number of arguments in the function call should match the definition of the function.
Explanation:
The required argument are those argument that are passing to the method the in the right location order.In the required argument the number of arguments in the call method must match the definition of the function .
For example
def fun( s ): #function definition
print(s) #display s
fun('er')#calling
In this example there is function fun() in which we pass the argument 'er' we call that function from main() .The control moves to the function definition it checks the number of argument in the calling function fun() is matched with the definition of function fun() and print 'er'.
All the other option are not describing the required argument that's why this is incorrect option .
I phone because it stores things hil sends out things to other people
We have that the .xlsm <em>Format </em>is used to save Excel Macro-Enabled Workbook file
<h3>Formats</h3>
Generally file are saved in different formats for easy sorting and application on the operating system.
For instance if a music file is renamed and stored in a different format say .exe the audio file wont be recognised as an audio file and hence refuse to play.
e.g
- .exe for a windows appication
- ,mp3 for an audio file
- .xlsm here is used to save Excel Macro-Enabled Workbook file
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