All categories

3 years ago

What is the reflections over the x- and y-axes

1 answer:

5 0

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x).

You might be interested in

Which shape below does not have reflection symmetry can someone help me

Eva8 [605]

Answer:

I would say the TRIANGLE because it has none of the lines that a symmetry has.

6 0

3 years ago

PLEASE HELP<br> What is the measure of ∠I? Explain.<br> Describe the relationship between ∠H and ∠L.

Llana [10]

The Relationship between Angle H and Angle L is that they are Corresponding Angles. Corresponding Angles are angles that equal to each other and are on the same side of the tranversal.

Sorry I don't know the answer to the first one without numbers. Hope that helped!

3 0

2 years ago

PLEASE HELP

Neko [114]

Answer:

1/36

Step-by-step explanation:

6^-2

~Use negative exponent rule [ a^-b = 1/a^b ]

1/6^2

1/36

Best of Luck!

6 0

3 years ago

Read 2 more answers

Suppose you want to transform the graph of the function into the graph of the function . Which transformations should you perfor

nexus9112 [7]

Answer:

A. Reflect the graph of the first function across x-axis, translate it $\frac{\pi}{4}$ to the left, and translate it 2 units up.

Step-by-step explanation:

We have the original function is $y=\tan (x+\frac{\pi}{4})-1$ .

The new transformed function is given by $y=-\tan (x+\frac{\pi}{2})+1$ .

So, we can see that the following sequence of transformations have been applied to the original function:

1. The function f(x) is reflected about x-axis i.e. f(x) becomes -f(x), which gives $y=-\tan (x+\frac{\pi}{4})-1$

2. This function obtained is translated $\frac{\pi}{4}$ units to the left i.e. $y=-\tan (x+\frac{\pi}{4}+\frac{\pi}{4})-1$ i.e. $y=-\tan (x+\frac{\pi}{2})-1$

3. Finally, this new function is translated 2 units upwards i.e. $y=-\tan (x+\frac{\pi}{2})-1+2$ i.e. $y=-\tan (x+\frac{\pi}{2})+1$

Hence, after applying, 'reflection across x-axis, translation of $\frac{\pi}{4}$ to the left, and translation of 2 units up', we get the required function.

3 0

3 years ago

Read 2 more answers

The mean and standard deviation of a random sample of n measurements are equal to 34.5 and 3.4, respectively.A. Find a 95 % conf

lora16 [44]

Answer:

a. The 95% confidence interval for the mean is (33.52, 35.48).

b. The 95% confidence interval for the mean is (34.02, 34.98).

c. n=49 ⇒ Width = 1.95

n=196 ⇒ Width = 0.96

Note: it should be a factor of 2 between the widths, but the different degrees of freedom affects the critical value for each interval, as the sample size is different. It the population standard deviation had been used, the factor would have been exactly 2.

d. 5. Quadrupling the sample size while holding the confidence coefficient fixed decreases the width of the confidence interval by a factor of 2.

Step-by-step explanation:

a. We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=34.5.

The sample size is N=49.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{49}}=\dfrac{3.4}{7}=0.486$