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Anna35 [415]
3 years ago
8

How do you find equivalent ratios? (Please put explanation)

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0
Two ratios that are equivalent are the same in value. We call these equivalent ratios. To find an equivalent ratio multiply or divide both of the numbers by a common number (or same number), this would be the exact same when finding equivalent fractions as well.
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Fill in the missing work and justification for step 2 when solving 3(x + 2) = 12.
liq [111]

Answer:

2

Step-by-step explanation:

3(x+2)=12

Distribute:

3x+6=12

Subtract:

3x+6-6=12-6

3x=6

Divide:

x=2

4 0
3 years ago
출<br> Enter the difference as a mixed number,<br> 10<br> Pls help me
krok68 [10]

Answer: 48/10

Step-by-step explanation: 65/10 - 17/10 = 48/10 also known as 4 8/10

8 0
3 years ago
Read 2 more answers
Find the marginal profit of C(x)=5x^2, R(x)=x^3+7x+10 and find all values of x for which the marginal profit is zero.
jonny [76]
Marginal profit, P(x) = R(x) - C(x)

P(x) = x³ - 5x² + 7x + 10

x³ - 5x² + 7x + 10 = 0
If you solve it, you get x = -0.839 where P(x) is zero

4 0
3 years ago
A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
lions [1.4K]

Answer:

Approximately 24–36 pounds

Step-by-step explanation:

Given:

Weight of standard American Eskimo dog has mean= 30 pounds

A standard deviation= 2 pounds

For 99.7% of the dogs according to normal distribution would lie between 3 standard deviations on either side of the mean.

i.e. lower bound= Mean- 3 (standard deviation)

= 30-3(2)

=30-6

=24

Upper bound = Mean +3 (standard deviation)

= 30+3(2)

=30+6

=36

Hence the range of weights : 24-36 pounds

correct answer Approximately 24–36 pounds!

4 0
3 years ago
Write the equation for a line in standard form (Ax+By+C) that is perpendicular to y = 3x -
salantis [7]

Answer:

x+3y-6=0

Step-by-step explanation:

given eqn is y=3x-2 which is 3x-y-2=0

the eqn of line perpendicular to given eqn is -x+3y+k=0

it passes through (6,4)

-6+3*4+k=0

or,. -6+12+k=0

or, k= -6

therefore, the eqn of line perpendicular to given eqn is x+3y-6=0

8 0
4 years ago
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