Sam said the square root of a rational number must be a rational number. Jenna disagreed. She said that it is possible that the

Question

hodyreva [135]

3 years ago

13

Sam said the square root of a rational number must be a rational number. Jenna disagreed. She said that it is possible that the

square root of a rational number can be irrational. Who is correct and why?

Mathematics

2 answers:

Nat2105 [25] · Answer 1 · 2022-03-13T21:30:14+03:00

Nat2105 [25]3 years ago

6 0

Jenna is correct. This is because the square root of 2 is an irrational number. And if the number is a prime number, the answer is less likely to have a rational square root.

Rzqust [24] · Answer 2 · 2022-03-13T23:29:33+03:00

Answer: Jenna is correct.

Step-by-step explanation:

We can prove this statement with help of two examples.

Since we know that 64 is the rational number.

And, the square root of 64 is $\sqrt{64}$ .

Which is equal to 8 or -8.

And, they are integers, and we know that the integer are always a rational number.

Therefore $\sqrt{64}$ is a rational number.

And, If we take a number 2 which is a rational number.

Since, when we do square root of 2, we get √2.

And, √2 is a irrational number.

Thus, we can say that we can obtain a rational or irrational number after doing the square root of rational number.

Therefore, Jenna is correct.