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dangina [55]
2 years ago
7

6. At a game, there were 24 adults and 10 children. Keeping the same ratio,

Mathematics
1 answer:
irina1246 [14]2 years ago
6 0

Answer:

The total number of adults will be: 120 adults

Step-by-step explanation:

Given that there were 24 adults and 10 children in a game.

Thus, adults to children ration = 24:10 or 24/10

  • If there were 50 children, how many adults would be at the game?

Let 'x' be the number of adults when there 50 children.

so the ration of adults 'x' to 50 childern = x: 50 or x / 50

As the ratio is the same.

Thus,

24 : 10 = x : 50

24/10 = x/50

switching sides

x/50  = 24/10

x  = 24/10 × 50

x = 120 adults

Therefore, the total number of adults will be: 120 adults

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Find the number of ways to distribute six different toys to three different children such that each child gets at least one toy.
Lisa [10]

Answer:

Step-by-step explanation:

Given that there are six different toys and they are to be distributed to three different children.

The restraint here is each child gets atleast one toy.

Let us consider the situation as this.

Since each child has to get atleast one toy no of ways to distribute

any 3 toys to the three children each.  This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways

So 3 toys to each one in 6x5x4 =120 ways

Now remaining 3 toys can be given to any child.

Hence remaining 3 toys can be distributed in 3x3x3 =27 ways

Total no of ways

= 120(27)

= 3240

8 0
2 years ago
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8 0
3 years ago
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lozanna [386]

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31.2

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6 0
2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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