A hollow ball is made of rubber that is 1 centimeter thick. The ball has a radius of 5 centimeters at the outside surface.

2 answers:

4 0

Given that the ball has a thickness of 1 cm and the radius at the outside is 5 cm, thus the radius from inside is 5 - 1 = 4cm.

The <span>approximate volume of rubber used to make the ball is given by the volume of the ball at the outside surface minus the volume of the ball at the inside surface.

i.e.
</span>
<span> $Volume\ of\ rubber= \frac{4}{3} \pi\left(5^3-4^3\right) \\ \\ = 
\frac{4}{3} \pi(61)= \frac{244}{3} \pi\approx255.5\ cm^3$ </span>

kirill115 [55]2 years ago

3 0

Answer: I got the same answer. It's 255.4 cm3

Step-by-step explanation:

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Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls

soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is when the graph touches the y-axis and when that happens x = 0.

$\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1$