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Oksana_A [137]
3 years ago
11

2.–/1 pointsMy Notes

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
What is "b" ???????????
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Prove algebraically that (m + 2)2 – m 2 – 12 is always a multiple of 4
Julli [10]

Answer:

(m + 2)^{2} - m^{2}  - 12 = 4(m - 2)

Step-by-step explanation:

Step 1:

Write the expression

(m+2)^{2} - m^{2}  - 12

Step 2: Expand (m + 2)^{2}

(m+2)^{2} - m^{2} - 12\\(m+2)(m+2) - m^{2}  - 12\\m^{2} + 2m + 2m + 4 - m^{2}  - 12

Step 3: Collect similar terms

m^{2}  - m^{2}  + 4m + 4 - 12\\4m - 8

Step 4: Factor 4 out of the expression to prove that the expression is a multiple of 4.

Therefore\\4m - 8 = 4(m - 2)\\Hence,\\(m+2)^{2}  - m^{2} -  12 is a multiply of 4 because the expression is equal to 4(m-2)

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To what expression must 5a square-4a+3 be added to make the sum zero??​
pychu [463]

Answer:

Step-by-step explanation:

Additive inverse of (5a² - 4a + 3) should be added to make them zero

(5a² - 4a + 3) + (-5a² + 4a - 3)=   <u>5a² - 5a² </u>  <u>- 4a + 4a</u>    <u>+ 3  - 3</u>

                                              = 0

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