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DaniilM [7]
3 years ago
8

If AC=12, BC=3, find CE 1) 3 square root of 3 2) 6 3) 18

Mathematics
2 answers:
azamat3 years ago
7 0

Answer:

2) 6

Step-by-step explanation:

CE^2 = BC * AC

CE^2 = 3 * 12

CE^2 = 36

CE = 6

NARA [144]3 years ago
6 0

Answer:

2) 6

Step-by-step explanation:

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Answer:

Sam ate the most pizza.

Step-by-step explanation:

Mathew: 0.8 is equal to 80%

To get a percentage, you need to move the decimal two places to the right.

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320% of 69 is what number?
DENIUS [597]

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220.8

Step-by-step explanation:

I believe 220.8

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3 0
3 years ago
Read 2 more answers
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Hello!

You draw a table or write this out

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5 0
3 years ago
Help guys<br>make p da subject of the formula<br>​
Basile [38]

Answer:

p=\dfrac{m}{k-s}

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression y=mx+b, for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

1=\dfrac{pk}{m+sp}

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

m+sp=pk

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that <em>sp</em> and <em>pk</em>. Let's collect them on the right side by subtracting <em>sp </em>from both sides:

m=pk-sp

p is a <em>common factor</em> of both <em>sp </em>and <em>pk</em>, so we can peel it away using the distributive property:

m=p(k-s)

And from here, we can divide both sides by k-s and we'll have p as our subject:

\dfrac{m}{k-s}=p or p=\dfrac{m}{k-s}

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

p=\frac{4}{2-0} =\frac{4}{2}=2

3 0
3 years ago
I NEED HELP PLEASE IM BEGGING YOU PLEASE HELP!!<br> IM B EGGING YOU PLEASE!!
Monica [59]

Answer:

are there any answer choices?

3 0
3 years ago
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