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kogti [31]
3 years ago
13

State any restrictions on the variables.

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0
The fraction that you have can be simplified
3y(y-1)/y-1,
we will simplify y-1 from both sides(they get cancelled)
and your answer is 3y, therefore, no restrictions are needed <span />
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X − 3 − 2(6 − 2x) = 2(2x − 5)
Finger [1]

Multiply the first bracket by -2

Multiply the second bracket by 2

x-3-12+4x= 4x-10

- negative number times + positive number= - negative number

- negative number times -negative number = + positive number

x+ 4x-3-12= 4x-10

5x-15= 4x-10

Move 4x to the other side

5x-4x-15= 4x-4x-10

x-15= -10

Move -15 to the other side

x-15+15= -10+15

x= 5

Answer : x= 5

7 0
3 years ago
Read 2 more answers
The verticals of a right triangle are (0, -6), (6, -3), and (x, -6). Find the value of x.
Nataly [62]
(0,-6), (6, -3), and (6,-6)

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6 0
3 years ago
Por favor me podrían ayudar y dar un ejemplo de cómo llevar a cabo
iogann1982 [59]

Answer:

g

Step-by-step explanation:

7 0
2 years ago
Evaluate ∫ e3x cosh 2x dx A.1/ e5x+1/ex+C 10 2 B. 1/ e3x + 1/ x + C 42 C. 1/ e5x + 1/ 10 5 x + C D. 1/ e5x + 1/ ex + C 22
Irina18 [472]
Sh(2x) = (e^2x + e^-2x)/2 

<span>Thus the integral becomes </span>

<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>

<span>= e^5x/10 + e^x/2 + C 
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
3 0
3 years ago
A wallet that holds $25 contains the same number of $1 bills, $5 bills, and quarters. How many of each type of bill or coin does
Anastasy [175]
<span>The wallet contains 4 $1 bills, 4 $5 bills, and 4 quarters.

$1 </span>× 4 = $4
$5 × 4 = $20
$0.25 × 4 = $1
$4 + $20 = $24, $24 + $1 = $25.
3 0
3 years ago
Read 2 more answers
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