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Umnica [9.8K]
4 years ago
11

Pamela rose her bike at a constant rate of 0.1 kilometer per minute?

Mathematics
1 answer:
Fed [463]4 years ago
3 0

Answer:

Step-by-step explanation:

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Can someone help me ??
belka [17]

Answer:

1, 3

Step-by-step explanation:

I took the test

6 0
2 years ago
3) Find the value of FD. bited F 12 12 13x - 16 E 4x+11 D​
vlada-n [284]

The Length of FD = 26 cm

According to the given information

FE = FC = 12cm

As FE, FC both are radius of circle

The tangent segments to a circle from a external point are equal

Hence

CD = ED

13x - 16 = 4x + 11

13x - 4x = 11 + 16

9x = 27

x = 27/9

x = 3

CD = 13x - 16

     = 13 × 3 - 16

     = 23 cm

ED = 4x + 11

     = 4 × 3 + 11

     = 23 cm

In Triangle FED

FE is perpendicular to ED

According to Pythagoras Theorem

FD^{2}= FE^{2}+ED^{2}

       = 12^{2}+ 23^{2}

       = 673

FD = 26 cm approx.

The Length of FD = 26 cm

To know more about Pythagoras Theorem

brainly.com/question/343682

#SPJ1

8 0
1 year ago
A student loses a uniforms
Anna35 [415]

Answer:

Please ask a question so the community can help answer it and it has to be a school subject not a real life situation.

6 0
3 years ago
Write the set of real numbers x less than 6 in set builder notation
maksim [4K]

Answer:

{x ∈ R: x<6}

Step-by-step explanation:

Given

  • x is a real number
  • x is less than 6

Required

Write the set using set builder notation

The very first thing to do is to list out the range of x, using inequalities;

x is less than 6 implies that -infiniti < x < 6

The next step is to translate this to set builder. This is done as follows

x ∈ R - > This means that x is a real number

x < 6 -> where x is less than 6.

Bringing these two together, it gives:

{x ∈ R: x<6}

Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation

6 0
3 years ago
I need to know how to get the answer and what the answer is
Vedmedyk [2.9K]
(Can't really explain it... hopefully these steps can help you.. maybe I'm just too lazy..)

2h^3j^-3k^4
-----------------
3jk

2h^3k^4
= -------------
3j^4k


2h^3k^3
= --------------
3j^4
8 0
3 years ago
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