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3 years ago

Solve the inequality 4(a+6) >= 5(a+3)

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

Solving the inequality $4(a+6) >= 5(a+3)$ we get $a\leq 9$

Step-by-step explanation:

We need to solve the inequality: $4(a+6) >= 5(a+3)$

Solving:

$4(a+6) \geq 5(a+3)\\4a+24\geq 5a+15\\4a-5a\geq 15-24\\-a\geq -9\\$

When we divide both sides by -1, the inequality is reversed i.e greater than equal to(≥) is changed into less than equal to(≤)

$a\leq 9$

Solving the inequality $4(a+6) >= 5(a+3)$ we get $a\leq 9$

Keywords: Solving inequalities

Learn more about Solving inequalities at:

#learnwithBrainly

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Uncle Bill has planted fruits in the farm and 7/12 is watermelon.2/3 of the watermelon section is ruined from the storm.The rest

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<h3>Fractions and proportion</h3>

Fractions are written as a ratio of two integers. The given question will be solved using the method of proportion.

If Uncle Bill has planted fruits in the farm and 7/12 is watermelon, and 2/3 of the watermelon section is ruined from the storm, the fraction ruined from the storm is;

Fraction ruined from the storm = 2/3* (7/12)

Simplify to its lowest term to have:

Fraction ruined from the storm = 7/18

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2 years ago

Does anyone know this answer??

Aleonysh [2.5K]

For this case we have the following equation:

$(2x + 3) ^ 2 + 8 (2x + 3) + 11 = 0$

Let $u = 2x + 3$

We have:

$u ^ 2 + 8u + 11 = 0$

By definition, given an equation of the form $ax ^ 2 + bx + c = 0$

The quadratic formula, to find the solution can be written as:

$x = \frac{-b+/-\sqrt{b ^ 2-4 (a) (c)} }{2(a)}$

In this case we have:

$a = 1\\b = 8\\c = 11$

Substituting in the quadratic formula we have:

See attached image

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