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Anarel [89]
3 years ago
15

Solve and graph -4 + 2t - 14 - 18t > -6 - 100t

Mathematics
1 answer:
irina [24]3 years ago
7 0
Okay so first u just add the terms on each side 
2t-18>-6-100t  
2(t-9)>2(-3-50t)
t-9>-3-50t
51t>6
t>6/51
t>2/17
so just take a number line put an empty circle like this : O on 2/17 and draw a line showing it continues to the right infinitely. Sorry if my math is wrong lol i am functioning on one hour of sleep. 
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In the diagram below, AB is parallel to CD. What is the value of x?
garik1379 [7]

The correct answer is: Option (D) x = 72°

Explanation:

When two lines are crossed by another line, the angles in matching corners are called <em>corresponding angles</em>. When the two lines are <em>parallel</em>, the corresponding angles are <em>equal</em>.

Here in this case, the two lines are "AB" and "CD", and both are parallel and are crossed by the line; therefore, <em>the corresponding angles will be the same</em>.

Since the first corresponding angle is 72°, the second angle <em>x </em>will be 72° as well. The correct answer is: x = 72° Option (D).

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For which value of m does the graph of y = 18x2 + mx + 2 have exactly one x-intercept?
Rashid [163]
Y = 18 x² + m x + 2
Exactly one x - intercept is for:
D = m² - 4 · 18 · 2 = 0
m² - 144 = 0
m² = 144
Answer:
m = -12 or m = 12 
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Eric and four of his friends are taking a trip across the New York State thruway they decide to split the cost of tolls equally
Free_Kalibri [48]

Answer: Since 5 is an odd number each person would then have to pay 1.60 each.

Step-by-step explanation:

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HURRY what is the simplified form of the following expression? 25xy sqrt 81/625 x^2 y^2
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The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08
kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So \mu = 10*0.08 = 0.8

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a p = 0.4493 probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

0.03% probability that none of the 10 cars has any surface flaws

(c) If 10 cars are sold to a rental company, what is the probability that at most 1 car has any surface flaws?

At least 9 cars without surface flaws. So

P(X \geq 9) = P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.4493)^{9}.(0.5507)^{1} = 0.0041

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0041 + 0.0003 = 0.0044

0.44% probability that at most 1 car has any surface flaws

5 0
3 years ago
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