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3 years ago

Solve for F. Let m=5, a=3 F=ma

Mathematics

1 answer:

GrogVix [38]3 years ago

4 0

The answer will be: F= 5*3 = 15

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I don’t understand this please help .

Ivahew [28]

Answer:

because its not the average

Step-by-step explanation:

it may be in the middle of the graph but its not the average(which would be the center), and if you do the math it would end up making 7 the average

hope this helps

6 0

3 years ago

Write the number 1/10,000,000 as a power of 10 using a negative exponents

allochka39001 [22]

First, convert into a decimal:

1/10,000,000 = 0.00000001

Next, convert to "the number with a power of 10 using a negative exponent. Move the decimal point to the first <em>number that is not 0</em> (sorry, there is a term for it, but i can't remember it right now, but it is not important to solving the answer)

0.000001 = 1 * 10^-7

1 * 10^-7 is your answer

8 0

3 years ago

Pleaseeeeeeeeeeee

Karo-lina-s [1.5K]

$\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a$

$a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}$

$b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}$

$c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}$

$Used:\\\\a^n\times a^m=a^{n+m}\\\\a^n\div a^m=a^{n-m}\\\\(a^n)^m=a^{n\cdot m}$

5 0

3 years ago

How do I do numbers 12 to 14?

NARA [144]

Answer:

12. 1 second, 35 ft; 2 seconds, 32 ft

13. (t, y) = (1.4 seconds, 37.6 feet)

14. 37.6 ft; the vertex is the highest point

Step-by-step explanation:

12. You have properly answered question 12.

After 1 second, the height is 35 feet; after 2 seconds, it is 32 feet.

13. My method of choice is to plot the graph on a graphing calculator and let it show me the coordinates of the vertex when I highlight that point. (See attached.) The vertex is ...

(t, y) = (1.4, 37.6)

14. The graph is a graph of height when the object is launched with a vertical velocity of 45 ft/s. So, the maximum of the graph will correspond to the maximum height of the object. The vertex is that maximum point, and its y-coordinate is that maximum height.

The maximum height is 37.6 feet.

8 0

3 years ago

Solve the given initial-value problem. <br> (2y + 2t − 3) dt + (8y + 2t − 1) dy = 0, y(−1) = 2.

katrin2010 [14]

Answer:

holy ish ive never seen anything like this in my life

Step-by-step explanation:

7 0

3 years ago