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dybincka [34]
3 years ago
7

Solve for F. Let m=5, a=3 F=ma

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0
The answer will be: F= 5*3 = 15
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Explain why their are no solutions to the system of inequalities <br> y ≤2x-5 <br> y ≥2x+1
rosijanka [135]

Answer:

Sorry this is late and I think this is right.

They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.

For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:

<em>y < - 1/2x -3</em>

<em>y > 1/2x + 2</em>

<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.

I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.

7 0
3 years ago
Year Number of Dropouts 1 7 2 8 3 6 4 6 5 6 6 4 7 4 8 1 9 2 10 7 11 6 12 1 13 1 14 1 15 3 16 3 17 5 18 4 19 5 20 7 The table giv
nadya68 [22]
Population mean = (7+8+6+6+6+4+4+1+2+7+6+1+1+1+3+3+5+4+5+7) / 20 = 87/20 = 4.35 <==

sample mean = (4+5+7) / 3 = 16/3 = 5.33 <==
6 0
3 years ago
Read 2 more answers
Question 20 fast please
kipiarov [429]

Answer:

Square root of 4 is 2

so  1+\frac{[1+\sqrt{2x-1]}^2 }{4}=4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

sqrt{2x-1}=V12-1

2x-1=(V12-1)^2=12-2V12+1=13-2V12

2x=13+1-2V12

2x=14-2V12

x=7-V12

x=7-2V3

I put an attachment to explain better

   

Step-by-step explanation:

6 0
3 years ago
What is 6 2/3 - 1 1/2
Alex17521 [72]

Answer:

=7/6

Step-by-step explanation:

= 20/3-11/2

= 7/6

You should use calculator.

5 0
3 years ago
Read 2 more answers
Write two numbers so that the numbers are in order _ ;6,010;_ ;5,060
Nastasia [14]
6,050 before 6010 then 5080 after 5060 or basically any numbers that are greater than the one to the left of it :))
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3 years ago
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