Distance = speed rate x time
Speed rate = 120 miles per hour
Time = 3 hours
Replacing:
D = 120 mph x 3 h = 360 miles
A. (H, 1) (H, 2) (H, 3) (H, 4) (H, 5), (T, 1) (T, 2) (T, 3) (T, 4) (T, 5)
grigory [225]
B
m,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Answer:
$1,109.62
Step-by-step explanation:
Let's first compute the <em>future value FV.</em>
In order to see the rule of formation, let's see the value (in $) for the first few years
<u>End of year 0</u>
1,000
<u>End of year 1(capital + interest + new deposit)</u>
1,000*(1.09)+10
<u>End of year 2 (capital + interest + new deposit)</u>
(1,000*(1.09)+10)*1.09 +10 =
<u>End of year 3 (capital + interest + new deposit)</u>
and we can see that at the end of year 50, the future value is
The sum
is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to
and the future value is then
The <em>present value PV</em> is
rounded to the nearest hundredth.
Answer:
36
Step-by-step explanation:
1-40% = 1-0.4=0.6 or 60%
60% not good at art.
60*60% = 60*6/10 = 6*6 = 36
Answer:
0.6,0.7,0.3 neither disjoint nor independent.
Step-by-step explanation:
Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.
A= visa card
B = Master card
P(A) = 0.60 and P(B) = 0.40
P(AUB)' = 0.30
i.e. P(AUB) = 0.70
Or P(A)+P(B)-P(AB) =0.70
P(AB)= 0.30
Randomly select a student from the university.
1) the probability that this student does not have a MasterCard.
2. the probability that this student has either a Visa card or a MasterCard.
=
3. Calculate the probability that this student has neither a Visa card nor a MasterCard.
=
4. Are the events A and B disjoint? Are the events A and B independent?
A and B have common prob 0.30 hence not disjoint.
P(AB) ≠P(A)P(B)
Hence not independent