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Irina-Kira [14]
4 years ago
13

The length of a rectangle is 4 less than twice the width. The area of the rectangle is 70

Mathematics
1 answer:
Iteru [2.4K]4 years ago
6 0
w = -5 ; w = 7

Area = Length * Width
Length = 2w - 4
Width = w

70 = (2w - 4)w
70 = 2w² - 4w
2w² - 4w - 70 = 0
2(w² - 2w - 35) = 0
2(w + 5) (w - 7) = 0
w + 5 = 0       ;  w -7 = 0
      w = -5      ;       w = 7

<span>w = -5 is not viable because no length of measurement is negative. </span>
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The diagram shows two parallel lines and a traversal. If the measure of ∠2 is 47°, what is the measure of ∠3?
goldenfox [79]

Answer:

The answer is b.133

Step-by-step explanation:

180 is a straight line and if angle 2 is 47 then angle 3 would be 133 because 133+47=180

6 0
4 years ago
The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
vagabundo [1.1K]

Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

8 0
4 years ago
Read 2 more answers
Find the indicated length.<br> Line WX bisects YZ at point W. Find YZ if WZ=9 5/8
Montano1993 [528]

Given :

Line WX bisects YZ at point W.

WZ=9\dfrac{5}{8}=\dfrac{77}{5} .

To Find :

The length of YZ .

Solution :

Since , the point W bisect YZ .

So , it cuts YZ into two equal parts i.e YW and WZ .

Therefore , YW = WZ

Also , YZ = YW+WZ = 2WZ

YZ = 2\times \dfrac{77}{5}\\\\YZ=\dfrac{154}{5}\\\\YZ=30\dfrac{4}{5}

Hence , this is the required solution .

8 0
3 years ago
A plumber charges $15 for transportation and $40 per hour for repairs complete the expression that can be used to find the cost
qwelly [4]

Answer:

y = 45x + 15

Step-by-step explanation:

7 0
3 years ago
What are the coordinates of the image of point K(1, 3) after a reflection over the line y = –1
ale4655 [162]

Answer:

1, -5

Step-by-step explanation:

you can this solve easily

3 - -1 = 4 units down from y = -1

x does not change in this reflection

4 0
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