Answer:
The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb
P(x⁻< 15) = 0.1587
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the size of the sample 'n' =49
Mean of the Population = 17ppb
The standard deviation of the population = 14ppb
Let 'X' be the random variable in a normal distribution
<u><em>Step(ii):</em></u>-
The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb
P(x⁻< 15) = P(Z<-1) = 1-P(Z>-1)
= 1-(0.5+A(-1))
= 0.5 - A(1)
= 0.5-0.3413
= 0.1587
<u><em>Final answer:-</em></u>
The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb
P(x⁻< 15) = 0.1587
Answer:
Theta = 0, 60 degrees.
Step-by-step explanation:
2 sin^2 theta + 3 cos theta = 3
Using the identity sin ^2 theta = 1 - cos^2 theta :
2(1 - cos^2 theta) + 3 cos theta = 3
2 - 2cos^2 theta) + 3 cos theta = 3
2 cos^2 theta - 3 cos theta + 3 - 2 = 0
2 cos^2 theta - 3 cos theta + 1 = 0
(2 cos theta - 1)(cos theta - 1) = 0
cos theta = 1/2 , cos theta = 1
Theta = 60 degrees or theta = 0
Answer: C
First you have to get rid of the 8 because it is a constant. -4-8=-12. Then, you multiply out the denominator to isolate the variable. This means -12*3=-36
Answer:
O the circumcenter is equidistant to all three vertices
Step-by-step explanation:
Answer:
x = 30.5 degree
Step-by-step explanation:
take angle x as reference angle
using sin rule
sin x = opposite / hypotenuse
sin x = 3.4 / 6.7
sin x = 0.507
x =
x = 30.46
x = 30.5 degree