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yawa3891 [41]
3 years ago
10

3. Consider the functions f(x) = x2 + 10x – 5, g(x) = 8x + 1, and h(x) = 3x – 4. List the functions from least to greatest value

when x = 3 and when x = 6. Then tell how you would explain to someone that you do not need to do any calculations to know the order of the functions when x = 15.
Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0
<u>x = 3</u>
f(x) = x²+ 10x - 5
f(3) = (3)² + 10(3) - 5
f(3) = 9 + 30 - 5
f(3) = 39 - 5
f(3) = 34

g(x) = 8x + 1
g(3) = 8(3) + 1
g(3) = 25

h(x) = 3x - 4
h(3) = 3(3) - 4
h(3) = 9 - 4
h(3) = 5

<u>x = 6
</u>f(x) = x² + 10x - 5
f(6) = (6)² + 10(6) - 5
f(6) = 36 + 60 - 5
f(6) = 96 - 5
f(6) = 91

g(x) = 8x + 1
g(6) = 8(6) + 1
g(6) = 48 + 1
g(6) = 49

h(x) = 3x - 4
h(6) = 3(6) - 4
h(6) = 18 - 4
h(6) = 14

I would explain to someone that you don't need to do any calculations to know the order of the functions when x is equal to 15 by knowing that f(x) is equal to 370, g(x) is equal to 121, and h(x) is equal to 41 to know that it is easy finding the function of x without calculating the answer.
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segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc
Elan Coil [88]

Answer:

The magnetic field is B = 3.87 *10^{-6} \ T

Direction is inward

 

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

      The radius of  BC is  r_{BC} =  30 \ cm  =  0.30 \ m

      The radius of  DA is r _{DA} =  20 \ cm =  0.20 \ m

      The length of CD is  r_{CD} =  10 cm =  0.1 \ m

      The length of AB is  r_{AB} =  10 cm =  0.1 \ m

      The current is  I  =  11.4A

The magnetic field is mathematically represented as

      B =  B_{BC} +  B_{DA} + B_{CD} + B_{AB}

       B =  \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]

        Where

                 \theta_{BC} = \theta_{DA} =  \frac{2\pi}{3}

Where  \frac{2 \pi}{3}  =  120^o

                \theta_{CD} = \theta_{AB}  =  0^o

so

        B =  \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]

         B = 3.87 *10^{-6} \ T

The direction is into the page

    This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule  the direction of current is perpendicular to the direction of magnetic field so since  current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

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Vikki [24]

Answer:

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Step-by-step explanation:

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No one is answering i posted this question 2 times, this is my 3rd time please answer.
Dahasolnce [82]

Answer:

13

Step-by-step explanation:

First, fill in 3 boxes of the table using the given information (blue numbers on the attached table)

"Of the 32 students that have a cell phone, 19 students do not have a tablet."

The top row of the table is students who have a cell phone.  Therefore, place 19 in the box in this row that is in the "no tablet" column.

"Of the 70 students that have a tablet, 57 students do not have a cell phone."

The first column of the table is students who have a tablet.  Therefore, place 57 in the box in the 2nd row of this column.

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Find the "no cell phone" row and the "no tablet" column and place 11 in the box that coincides.

We can calculate the blank totals using addition (shown by green numbers on the attached table)

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To calculate the number of students who have a cell phone AND a tablet:

⇒ Total students with a cell phone <em>minus</em> students with a cell phone but no tablet

⇒ 32 - 19 = 13

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