PART A: The equation I used is y<span>≥-1x+4. The line will be graphed going diagonally from the second quadrant to the fourth quadrant and shaded above the line.
PART B: Plug in the coordinates for point C and F into the equation from PART A and solve them to make sure the statements are true. You should end up with 2</span>≥2 for point C and 4<span>≥1 for point F.
PART C: First graph the equation and then shade below the line. Next, identify all the points in the shaded area.
I hope this helps you! I have provided pictures of both equations for reference. The first picture is for PART A and PART B. The second picture is for PART C. Let me know if I'm correct :)</span>
(x - 3)^2
(x - 3) * (x - 3)
x^2 - 3x
+ -3x + 9
x^2 - 6x + 9
Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other
130 = x + 136
subtract 136 from both sides
x = -6
The formula for this is

. Filling in accordingly,

. This simplifies to

and 36=6x. Therefore, x = 6 so the bases are 6 and 12.