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Vanyuwa [196]
4 years ago
11

Find x when y = 5 in the literal equation 4x + 7y = 51

Mathematics
2 answers:
xeze [42]4 years ago
8 0
The answer is... x=4

4(4) + 7(5) = 51

Hope ive helped!
nataly862011 [7]4 years ago
3 0
Hey there!

All that you need to do for this problem is plug in 5 where you see "y" in your given equation. The term 7y indicates that you will be multiplying 7 and the y value together, so you'll multiply 7 by 5 to get the value of that whole term. 

4x+7y = 51

4x+7(5) = 51

4x+35 = 51

Now, just solve for x. You can do this by combining like terms and simplifying your equation as much as possible. Remember that addition cancels out subtraction and division cancels out multiplication and vice versa. What you do to one side is something you must do to the other side. 

(4x+35) - 35 = (51) - 35

(4x) = (16)

\frac{4x}{4} =  \frac{16}{4}

x =4

The value of x will be 4 if y is equal to 5. 

Hope this helped you out! :-)
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4 years ago
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yanalaym [24]
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2 fractions have the same denominator. Which is the greater fraction: the fraction with the greater numerator or thr lesser nume
irinina [24]
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So, which one is the greatest fraction?  In this case, who had more cookies?  That would be you.  So, the greater numerator means a greater fraction.

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5 0
3 years ago
The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
3 years ago
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