Give the domain and range. x –2 0 2 y –1 0 1 a. domain: {2, 0, 2}, range: {1, 0, 1} b. domain: {–2, 0, 2}, range: {–1, 0, 1} c.
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Step-by-step explanation:
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Answer:
The probability is 
Step-by-step explanation:
From the question we are told
The population proportion is 
The sample size is 
The number of graduate who had job is k = 209
Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

Generally the standard deviation of this sampling distribution is

=> 
=> 
Generally the sample proportion is mathematically represented as

=> 
=> 
Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as


From the z table the area under the normal curve to the left corresponding to -3.022 is

=> 
{(3x)}^{2}-2(3x)(5)+{5}^{2}
−2(3x)(5)+5
2
{(3x-5)}^{2}
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136
√34² + √136² =√170²
34 + 136 = 170
170 = 170
Answer:
a=1 or a=5
Step-by-step explanation:
+4=6a−1
Step 1: Subtract 6a-1 from both sides.
+4−(6a−1)=6a−1−(6a−1)
−6a+5=0
Step 2: Factor left side of equation.
(a−1)(a−5)=0
Step 3: Set factors equal to 0.
a−1=0 or a−5=0
a=1 or a=5
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