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vredina [299]
3 years ago
7

Answer to 38×21 using area model

Mathematics
1 answer:
docker41 [41]3 years ago
4 0
La respuesta correcta es 798 por que si multi plicas el valos agregado te daras cuenta que esa es la respuesta 
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|4a|=20<br> PLEASE HELPPPPPPPPPP
fgiga [73]

Answer:

The answer to |4a|=20 is a=5 or a=-5.

Step-by-step explanation:

6 0
3 years ago
Two consecutive negative integers have a product of 2. what are the integers ?
MrRissso [65]

product is multiplication

 2 negative numbers multiplied by each other equal 2

 since it is multiplication the numbers would need to be 2 or less

 therefore the 2 numbers are -1 and -2


-1 * -2 = 2

 

6 0
3 years ago
Write equivalent expressions using distributive property. m(4+7)
yulyashka [42]

Hey there!

m(4 + 7)

= 1m(4 + 7)

DISTRIBUTE m WITHIN the PARENTHESES

= m(4) + m(7)

= 4(m) + 7(m)


= 4(1m) + 7(1m)


= 4m + 7m


COMBINE the LIKE TERMS

= 11m


Therefore, your answer is: 11m


Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

4 0
2 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
Myfhrhahshsj t drtr srthsrt hrshrh rh rtj yj
viva [34]

? what was this ?

adkl ajøldskj aklødsj alkdsjalkjds køa jds

lol

7 0
3 years ago
Read 2 more answers
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