Answer:
<em>Center: (3,3)</em>
<em>Radius: </em>
<em />
Step-by-step explanation:
<u>Midpoint and Distance Between two Points</u>
Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:


The distance between both points is given by:

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:


Center of circle C: (3,3)
The radius of C is half the distance between A and B:


The radius of C is d/2:

Center: (3,3)
Radius: 
Answer:
a)
Let x = number of candy bars sold
Let y = amount of money earned
b)
y = 0.75x
c)
He should work at the car wash.
Step-by-step explanation:
a)
Let x = number of candy bars sold
Let y = amount of money earned
b)
$42.75/57 = $0.75
Each candy bar costs $0.75
We can confirm that by dividing $38.25/51 = $0.75
1 candy bar sells for $0.75
2 candy bars sell for $0.75 * 2
x candy bars sell for 0.75 * x, or simply 0.75x
The equation is y = 0.75x
c)
y = 0.75x
y = 0.75 * 36
y = 27
Larry raised $27 by selling candy bars last year. This year, he can earn more than that by working at the car wash.
He should work at the car wash.
Answer:1/2
Step-by-step explanation:
Given : Figure B is a scaled copy of Figure A.
We know that the scale factor is the ratio of the corresponding sides of two similar figures.
From , the graph we assume that that one point = one unit of length.
Then, the dimension of one side of figure A = 4 units and the dimension of corresponding side of Figure B = 2.
Then, the scale factor is given by 1/2
Step-by-step explanation:
<h3>Given:</h3>
<h3>To prove:
</h3>
<h3>Solution:</h3>
<u>CM⊥AB - given, therefore</u>
- ∠AMC = 90° and ∠BMC = 90°
<u>Then</u>
- Side CM is common, therefore is congruent to itself
<u>So we have congruent two angles and a side between them on triangles AMC and BMC:</u>
- △AMC ≅ △BMC as per ASA congruency theorem
Answer:
55
Step-by-step explanation:
Combination will be used here as teams are a group.
So using combination:
<em>No. of combination of 'n' things taken 'r' at a time</em>
<em>
=
</em>
here n = 11 ,
r = 9
11<em>C</em>9 <em>=
=
</em>
11<em>C</em>9<em> =</em><em> 55</em>
<em>Which are the possible 9 player starting lineups</em>