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uysha [10]
4 years ago
8

WILL GIVE BRAINLIEST! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the origin and

(−3, 4).
Mathematics
1 answer:
Lesechka [4]4 years ago
6 0

Answer:

Step-by-step explanation:

The distance between a point (x,y) and the point (-3,4) is

d1= \sqrt{ (x+3)2+(y-4)2} .

The distance between a point (x,y) and the point (0,0) is

d2= \sqrt{x2+y2} .

You know what y is from the equation of the line, so substitute that, set d1=d2, and solve for x.

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Serga [27]

Answer:

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Step-by-step explanation:

3a + 4a = -21

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To make it true...

3(-3) + 4(-3) =

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