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2 years ago

What the fraction of 0.13

Mathematics

2 answers:

Kay [80]2 years ago

6 0

Answer:

13/100 sorry thats the simplest its kind of obvious..

Mila [183]2 years ago

4 0

Answer: 13/100

I hope I helped.

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The product of consecutive odd integers is 575. what is the largest integer? 25 23 525 need more information

hichkok12 [17]

sqrt(575) = 23.979

so 23 is one number

575/23 = 25

the two numbers would be 23 * 25

25 is the largest one

4 0

3 years ago

Using the relationships between

Pavlova-9 [17]

Answer:

They will always intersect at one point

Step-by-step explanation:

6 0

1 year ago

For the rotation - 660°, find the coterminal angle from 0° < 0 < 360°, thequadrant and the reference angle.

guajiro [1.7K]

Given the angle:

-660°

Let's find the coterminal angle from 0≤θ≤360.

To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,

We have:

Coterminal angle = -660 + 360 = -300 + 360 = 60°

Therefore, the coterminal angle is 60°.

Since 60 degrees is between 0 to 90 degrees, is is quadrant I.

60 degrees lie in Quadrant I.

Also since it is in quadrant I, the reference angle is still 60 degrees.

ANSWER:

The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°

3 0

1 year ago

Simply the expression-2.3(4r+5)-3.6r

laiz [17]

Answer:

Step-by-step explanation:

you need to cancel out the brackets by multiplying -2.3 with every thing inside the brackets

3 0

3 years ago

Read 2 more answers

The manufacturer of a CD player has found that the revenue R (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com

AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

$R(p) = -5p^2 + 1550p$

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

$\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550$

Equating the first derivative to zero, we get,

$\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155$

Again differentiation R(p), with respect to p, we get,

$\dfrac{d^2(R(p))}{dp^2} = -10$

At p = 155

$\dfrac{d^2(R(p))}{dp^2} < 0$

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

$R(155) = -5(155)^2 + 1550(155) = 120125$

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0

3 years ago