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4 years ago

Evaluate ∫ e3x dx. A. e3x + C B.1/ e4x+C 4 C. e4x + C D. 1/3 e3x + C

1 answer:

5 0

Since the integral of (e^ax)dx = (1/a)(e^ax) + C, then in this case, we can let a = 3, and follow the formula to integrate this.
integral of (e^3x)dx = (1/3)(e^3x) + C, where C is an arbitrary constant.
This is choice D.

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