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3 years ago

A city’s population is increasing at a rate of 5% each year. Which type of model describes this situation?

Mathematics

1 answer:

Basile [38]3 years ago

8 0

Answer:

Exponential

Step-by-step explanation:

Ir's exponential because linear would mean it is increasing by a specific number every year, in which this case does not. Quadratic would mean a vertex form would need to be used, and with the information given , that could not happen.

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Let's evaluate 3x + 4 when x=5

Vladimir79 [104]

It is simple
Step 1) substitute x = 5 into the equation
3x +4
3(5) + 4 gives you 3 times 5 + 4
The answer is 15 + 4 which is 19

Now substitute a and b into the equation 3(a) + 4(b) when the a = 6 and b = 5
Hereby 3(6) + 4(5)
3 * 6 = 18 and 4* 5 = 20
18 + 20 = 38
The answer is 38

Now finally
Substitute a and b Into the equation
3(3) + 4(6)
9+ 24 = 33

6 0

3 years ago

The exchange rate in London is £1 = €1.14

MArishka [77]

Answer:

Paris

Step-by-step explanation:

In London we get

£1 = €1.14

In Paris we get

£0.86=€1

dividing both sides by 0.86 gives:

£1 = €1/0.86=€1.16 in Paris

so in Paris you get more € for the same £1

3 0

3 years ago

Anais bought 212 yards of ribbon. She had 1 feet 6 inches of ribbon left after trimming some curtains. How many inches of ribbon

victus00 [196]

Answer:

Step-by-step explanation:

3 0

3 years ago

Explain why each of the following integrals is improper. (a) 4 x x − 3 dx 3 Since the integral has an infinite interval of integ

erma4kov [3.2K]

Answer:

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Since the integral has an infinite interval of integration, it is a Type 1 improper integral

Since the integral has an infinite discontinuity, it is a Type 2 improper integral

Step-by-step explanation:

Considering a

$\int\limits^4_3 {\frac{x}{x- 3} } \, dx$

Looking at this we that at x = 3 this integral will be infinitely discontinuous

Considering b

$\int\limits^{\infty}_0 {\frac{1}{1 + x^3} } \, dx$

Looking at this integral we see that the interval is between $0 \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering c

$\int\limits^{\infty}_{- \infty} {x^2 e^{-x^2}} \, dx$

Looking at this integral we see that the interval is between $-\infty \ and \ \infty$ which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral

Considering d

$\int\limits^{\frac{\pi}{4} }_0 {cot (x)} \, dx$

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral

7 0

3 years ago

Help me plz show work

elena-14-01-66 [18.8K]

Answer:

I cant see the question

Step-by-step explanation:

The picture is just an error screen.

3 0

3 years ago