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Mariana [72]
3 years ago
12

How many different right triangles are there with a hypotenuse of lenght 5 cm

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer:

Draw a horizontal line across a page of paper, somewhere in the middle. Mark a point A on the line, toward the left margin.

Spread open a compass to make good sized circle, but so that if the point of the compass is on the point you drew, the pencil fits on the page, both below the top edge and to the left of the right edge of the page. Draw the arc, from roughly the 12 O’Clock position over and down to the intersection of the line segment, at the 3 O’Clock position.

Call the opening of your compass, the radius of the arc you just drew, “5 units”.

Pick any point on the arc between the 12 and 3 positions, B. Drop a line down from that point B, perpendicular to the original horizontal line. Label the point that it intersects the horizontal line, C.

ABC is a right triangle with hypotenuse 5. Do this again with a point a little closer to the 3 O’Clock position. It’s another right triangle with hypotenuse 5.

Indeed, as you get closer to the right, along the arc, the height of the triangle declines, but the width of the triangle increases. The hypotenuse remains 5 in all cases. We picked points on the circle. We could have picked points on the horizontal line first, and raised perpendicular lines until they intersected the circle. Each point forms a distinct right triangle.

There are as many possible right triangles as there are possible points in a line segment.

Step-by-step explanation:

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The vertices of a square are located at:
vivado [14]

Answer:

(4,4), (10,4), (10,10), (4,10)

Step-by-step explanation:

(2,2) x2 -> (4,4)

(5,2) x2 -> (10,4)

(5,5) x2 -> (10,10)

(2,5) x2 ->  (4,10)

Hope that helps!

5 0
3 years ago
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The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta
max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0
3 years ago
Simplify(1\2)^4 1\16 1\8 1\4
tino4ka555 [31]

Step-by-step explanation:

(1\2)^4 x 1\16 x 1\8 x 1\4 [1/2^4=16]

1/16 x 1/512

=>1/2048

5 0
3 years ago
Find the diameter(s) of circle O.
schepotkina [342]

Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

BC^2=r^2+r^2=2r^2

Thus we have

2r^2=(6\sqrt{2})^2

2r^2=72

r^2=36

r=6

The diameter of the circle O is D=2(6) = 12 units

5 0
3 years ago
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dangina [55]
If you're finding slope, the answer is 5/3
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