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Oksana_A [137]
3 years ago
12

Which three lengths could be the length of the sides of a triangle?

Mathematics
1 answer:
Firdavs [7]3 years ago
7 0
Answer is
<span>1: 6cm, 10cm, 9cm

6 + 10 > 9
6 + 9 >10
10  + 9 > 6

</span>
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What is the equation of a line parallel to y=4/5x+2 that passes through 1,2<br>​
givi [52]

Answer:

4/5x+6/5

Step-by-step explanation:

not sure but i have my ways with equations lol

6 0
3 years ago
Which of the following expressions is equal to 58?
77julia77 [94]

Answer:

sduusb

Step-by-step explanation:

sh dus u

6 0
3 years ago
A number cube is rolled. What is the probability of rolling a 2,3, or 5?
Liula [17]
Well if the number cube goes up to 6 like most number cubes, then the probability would be 3/6 because there are 3 numbers that you want to roll (2, 3, and 5) out of 6 total numbers (1-6). Then 3/6 can be further simplified to 1/2. So the answer should be 1/2.
4 0
3 years ago
At Billy‘s preschool they have bicycles and tricycles with a total of 57 wheels. The number of bicycles is three less than three
ikadub [295]
Use b for bicycles b and t for tricycles.

We know that each bicycle has 2 wheels, and each tricycle has 3 wheels, and if the entire number of wheels is 57, that means the 

equation would be: 2b + 3t = 57

We can "separate" b by calling it "25 - t" as an alternative, 

2(25 - t) + 3t = 57, or

50 - 2t + 3t = 57,

or 50 + t = 57, so

t = 7 So there must be 18 bicycles and 7 tricycles.

CHECKING:You can check this out by multiplying 7 tricycles x 3 wheels, which is 21,

and 18 bicycles x 2 wheels, which is 36

36 + 21 = 57
6 0
3 years ago
In Exercise 4, find the surface area of the solid<br> formed by the net.
Fittoniya [83]

Answer:

3. 150.72 in²

4. 535.2cm²

Step-by-step Explanation:

3. The solid formed by the net given in problem 3 is the net of a cylinder.

The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.

The surface area = Area of the 2 circles + area of the rectangle

Take π as 3.14

radius of circle = ½ of 4 = 2 in

Area of the 2 circles = 2(πr²) = 2*3.14*2²

Area of the 2 circles = 25.12 in²

Area of the rectangle = L*W

width is given as 10 in.

Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in

Area of rectangle = L*W = 12.56*10 = 125.6 in²

Surface area of net = Area of the 2 circles + area of the rectangle

= 25.12 + 125.6 = 150.72 in²

4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)

= 2(0.5*b*h) + 3(l*w)

Where,

b = 8 cm

h = \sqrt{8^2 - 4^2} = \sqrt{48} = 6.9 cm} (Pythagorean theorem)w = 8 cm[tex]S.A =  2(0.5*8*6.9) + 3(20*8)

S.A =  2(27.6) + 3(160)

S.A =  55.2 + 480

S.A = 535.2 cm^2

6 0
3 years ago
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