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3 years ago

The teacher still wont help

Mathematics

2 answers:

forsale [732]3 years ago

8 0

Answer:

18 licks per lollipop

Step-by-step explanation:

54 licks / 3 lollipops

2. 2 lollipops

3. 90 licks

stepan [7]3 years ago

7 0

Answer:

Step-by-step explanation:

54 ÷ 3 = 18

18 licks = 1 lollipop

18 x 2 = 36

36 licks = 2 lollipop

5 lollipop = ?

18 x 5 = 90

90 licks = 5 lollipop

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3.26 round to the nearest tenth

zaharov [31]

It's 3.3 because the 2 is in the tenths place and you look at 6 and say is it over 5? Yes it is so the next number after 2 is 3 so your answer is 3.3

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3 years ago

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What are the coordinates of one of the vertices of a rectangle when two sides are given by the lines x - 3y = -8 and 3x + y = 6?

Aleonysh [2.5K]

Answer:

(1, 3)

Step-by-step explanation:

x - 3y = -8

3x + y = 6

Isolate a variable in one of the equations:

y = 6 - 3x

Substitute the value of y into the other equation:

x - 3(6 - 3x) = -8

Use distributive property:

x - 18 + 9x = -8

Combine like terms:

10x - 18 = -8

Isolate the variable:

10x = 10

x = 1

Substitute the value of x into any equation:

3(1) + y = 6

3 + y = 6

Isolate the variable:

y = 3

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3 years ago

Find the total surface area of this cuboid

Harman [31]

Step-by-step explanation:

☄ $\underline{ \underline{ \sf{Given}}}:$

Length ( l ) = 4 cm
Width ( w ) = 2 cm
Height ( h ) = 5 cm

☄ $\underline{ \underline{ \sf{To \: find}}} :$

Total surface area of a cuboid

❅ $\underline{ \underline{ \text{Solution}}}:$

✑ $\boxed{ \text{TSA = 2lw + 2lh + 2hw}}$

Plug the known values :

⟼ $\sf{2 \times 4 \times 2 + 2 \times 4 \times 5 + 2 \times 5 \times 2}$

⟼ $\sf{16 + 40 + 20}$

⟼ $\boxed{\sf{76 \: {cm}}^{2} }$

$\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 76 \: {cm}}^{2} }}}$

Hope I helped !♡

Have a wonderful day / night ! ツ

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4 0

2 years ago

A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

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3 years ago

Just Seabra 5.2 pounds of grapes for $7.75 using the unit rate how much would 3 pounds of grapes cost

lora16 [44]

Answer: 4.47

Step-by-step explanation:

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3 years ago

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