Answer:
81.1 is the answer ..,eksks
The answer will be (10,2) because of the substitution method.
Answer:
141
Step-by-step explanation:
We need to first find the volume of the cannonballs and then, divide the volume of the closet by the volume of the cannonballs.
The radius of the spherical cannonball is 0.75 feet.
The volume of a sphere is:
![V = \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3)
where r = radius
Therefore, the volume of the cannonballs is:
![V = \frac{4}{3} * \pi * 0.75^3\\\\V = 1.77 ft^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%2A%20%5Cpi%20%2A%200.75%5E3%5C%5C%5C%5CV%20%3D%201.77%20ft%5E3)
Therefore, the number of cannonballs that can fit the closet is:
250 / 1.77 = 141.24
Since the number is a maximum and it must be a whole number, the number of cannonballs that can fit the closet is 141.
The perimeter is about 82 yards
first, the perimeter of the rectangles is 30*2 = 60 (the 7 is not a part of the overall perimeter so we do not need to add it)
the "perimeter" (circumference) of the 2 semi circles = (22/7)*7 = 22by using the formula C = pi*d (2 semi circles of the same diamter = 1 circle)
now just add the 2 answers
22 + 60
= 82 yards