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2 years ago

Consider this system of equations:

1 answer:

alexandr1967 [171]2 years ago

5 0

"For which value of k does the system have no real number solutions?"
The answer is 4, because 4+4≠16.

"For which value of k does the system have one real number solution?"
The answer is -0.25, because the linear line because tangent with the parent function.

"For which value of k does the system have two real number solutions?"
The answer is 2, because the linear function intercepts the parent function 2 times.

- i hope these are the answers you are looking for.

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What is the product of? (7x^2)(2x^3+5)(x^2-4x-9)

pav-90 [236]

$(7x^{2})(2x^{3} +5)( x^{2} -4x-9)
$
$(14 x^{5} +35 x^{2})( x^{2} -4x-9)$
= $14 x^{7} -56 x^{6}-126 x^{5}+35 x^{4}-140 x^{3}-315 x^{2}$

6 0

3 years ago

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A square patio has a area of 215 square feet. how long is each side of the patio to the nearest 0.05

Vanyuwa [196]

A square has all 4 sides the same.

When given the area of a square , you can find the length of the side by finding the square root of the area:

Side length = √215

Side Length = 14.6628

Rounding to the nearest 0.05 would = 14.65 feet.

8 0

2 years ago

Initial Knowledge Check

Cloud [144]

Answer:

I believe it would be five dollars since if you divide the price with the percentage yknow

5 0

2 years ago

4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B

AleksAgata [21]

Answer:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

$\hat p=\frac{63}{200}=0.315$ estimated proportion of lawyers had used some form of advertising for their business

$p_o=0.25$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.123)=0.0169$

8 0

3 years ago

2x + 4y = 22 2x - 2y = -8

NISA [10]

Answer:

2x+4y=22

-2x+2y=+8

6y=30

y=5

now

replace the value of y in equ i

2x +4y =22

2x+20=22

x=1

6 0

2 years ago

Read 2 more answers