A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
Part A) 25
Part B) 225
Step-by-step explanation:
Part A
The slope of the graph gives us the mile per gallon of the car.
Recall that the slope of the graph is rise over run.
Therefore car gets 25 miles per gallon
Part B) Since we know the slope of the direct variation line, we substitute into y=kx to get:
To find the number of miles the car travels using 9 gallons, we substitute x=9 to get:
This gives us 225 miles
Answer:
C
Step-by-step explanation:
The technical probability of rolling any number on a standard die is 1/6 because there's six numbers. Based on that, since he rolled a "4" on 5 tosses, it seems likely that it's 30 times, because 1/6 of 30 is 5. I haven't done probability in awhile but if I remember correctly that should be right
Answer 54 is the correct answer
LxWxH
Answer:
So it's a big probability it's a 6 in 4 chance though. 6 is for users that are careful and 4 for users that aren't that careful.
Step-by-step explanation:
