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weeeeeb [17]
3 years ago
5

-27=2x^2-4 PLEASE HELP ASAP

Mathematics
2 answers:
Nesterboy [21]3 years ago
6 0
X = [ (i sqrt46) / (2) ] ; - [ (i sqrt46) / (2) ]
Harlamova29_29 [7]3 years ago
4 0

Answer:

<h3>                NO REAL SOLUTIONS </h3>

and complex solutions:  \bold{x_1=\frac{ i\,\sqrt{46}}2\ ,\quad x_2=-\frac{ i\,\sqrt{46}}2}

Step-by-step explanation:

-27 = 2x² - 4

-2x² = 27 - 4

-2x² = 23

 x² = -23/2

means NO REAL SOLUTIONS  

(as there is no real number that put instead of x gives value less then 0)

However in complex numbers we have:

x=\pm\sqrt{-\frac{23}2}=\pm\sqrt{\frac{23}2}\cdot i=\pm\, i\sqrt{\frac{46}4}=\pm\frac{ i\,\sqrt{46}}2\\\\ x_1=\frac{ i\,\sqrt{46}}2\ ,\quad x_2=-\frac{ i\,\sqrt{46}}2

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Calculate the perimeter and area of the triangle formed by the coordinates K (-4,-1) ,L(-2, 2), and M (3,-1).
Y_Kistochka [10]

Perimeter = 16.4 units

Using the heron's formula, Area ≈ 10.4 units².

<h3>What is the Heron's Formula?</h3>

The heron's formula is used to find the area of a triangle with known side lengths of all its three sides, a, b, and c. The heron's formula is given as: Area = √[s(s - a)(s - b)(s - c)], where s = half the perimeter of the triangle

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Given the following:

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Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find KL, LM, and KM.

KL = √[(−2−(−4))² + (2−(−1))²]

KL = √13 ≈ 3.6 units

LM = √[(−2−3)² + (2−(−1))²]

LM = √34 = 5.8 units

KM = √[(−4−3)² + (−1−(−1))²]

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LM = b = 5.8 units

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Plug in the values into √[s(s - a)(s - b)(s - c)]

Area = √[8.2(8.2 - 3.6)(8.2 - 5.8)(8.2 - 7)]

Area = √[8.2(4.6)(2.4)(1.2)]

Area = √108.6336

Area ≈ 10.4 units²

Learn more about heron's formula on:

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