Answer:
p=7Q/2
Step-by-step explanation:
Original number of students:
p students to do 1 job in 25 days.
Let r= the rate for 1 student.
pr*25=1
pr*25=1 is the work rate equation for p students.
Lesser number of students:
p-Q students came to do the job and time required was 35 days.
(P-Q)*r*35=1.
The unknowns are p, Q and r
Equate the original number of students and the lesser number of students
pr*25=(P-Q)*r*35
25rp=35rp - 35Qr
Collect like terms
25rp-35rp = -35Qr
Divide both sides by -5
-5rp+7rp=- 7rp
It can be re written as
7rp-5rp=-7Qr
2rp=7Qr
Make p the subject of the formula
p=7Qr/2r
p=7Q/2
p=7Q/2 is the original number of students
-10rp = -35Qr
The system of these two equations can be solved for p. See the THREE unknown
variables, p, r, and Q. You might assume that either r or Q would be a constant.
16-3p=2/3p+5
add 3p to each side
16 = 3 2/3 p +5
subtract 5
11 = 3 2/3 p
change to an improper fraction
11 = (3*3+2)/3 p
11 = 11/3 p
multiply by 3/11 on each side
11 * 3/11 = 3/11 * 11/3 p
3 =p
Answer:
fill in the missing number on the number line
2350 2350
Answer:
We conclude that:
Step-by-step explanation:
Some background Concepts:
From the graph, it is clear that at x = -10, the graph intersects the x-axis.
So, the x-intercept of the graph is (-10, 0).
It means g(-10) = 0
From the graph, it is clear that at y = 5, the graph intersects the y-axis.
So, the y-intercept of the graph is (0, 5).
It means g(0) = 5
Determining g(-3):
From the graph, it is clear that at x = -3, the value of the function output = 3.5.
In other words,
at x = -3, g(-3) = 3.5
Therefore, we conclude that:
I thinks its 57/40 or as a fraction it's 1.425
