Answer:
can you please type it cause I can't see I help
By the quadratic formula,
Then
Multiply numerator and denominator by the denominator's conjugate:
Answer:
See below ~
Step-by-step explanation:
<u>P (6th grader)</u>
- No. of 6th graders / Total students
- 6 / 6 + 7 + 8
- 6/21
- 2/7
<u>P (6th grader after)</u>
- No. of 6th graders - 1 / Total students - 1
- 6 - 1 / 21 - 1
- 5/20
- 1/4
<u>Question 1 : P (Both 6th graders)</u>
- P = P (6th grader) × P (6th grader after)
- P = 2/7 x 1/4 = 2/28 = <u>1/14</u>
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<u>Question 2 : P' (Both 6th graders)</u>
- P' = 1 - P
- P' = 1 - 1/14
- P' = <u>13/14</u>
Answer:
<h2>
The width, x, of this parallelogram is 16 cm.</h2>
Step-by-step explanation:
In #14, the area of the parallelogram is 528 cm².
This area is also the value of the formula A = L·W:
A = 528 cm² = (33 cm)·W
To determine the width, W, of this parallelogram, we perform the following division:
W = (528 cm²) / (33 cm) = 16 cm
The width, x, of this parallelogram is 16 cm.
