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2 years ago

Solve the compound inequality for x and identify the graph of its solution.

Mathematics

1 answer:

ladessa [460]2 years ago

8 0

Answer:

x<-4 or x≤4

Step-by-step explanation:

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Kayla is on level 12 of a new game. Everyday she completes 6 new levels. Maddy is on level 28 of the same game. Everyday she com

ankoles [38]

Answer:

Kayla and Maddy will be in the same level in 4 days.

Step-by-step explanation:

Kayla: y = 6x + 12

Maddy: y = 2x + 28

6x + 12 = 2x + 28

Subtract 2x from both sides;

4x + 12 = 28

Subtract 12 from both sides;

4x = 16

Divide both sides by 4;

x = 4

3 0

3 years ago

Read 2 more answers

Which is a stretch of an exponential decay function? f(x) = f(x) = (5)x f(x) = 5 f(x) = 5(5)x

Goshia [24]

Answer:the answer is c on ed.

4 0

3 years ago

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Find the value of x the options are: 8 97 107 117 PLEASE HURRYYY

antiseptic1488 [7]

Answer:

107 degrees

Step-by-step explanation:

All polygon degrees add up to 360

we know that this polygon has a angle of 90 and 56

subtract 90 and 56 from 360 to get 214

Then divide by 2 because there are 2 x angles

to get 107 degrees

3 0

3 years ago

If the answer to the square root is 5, then what is the number that gets you 5

tensa zangetsu [6.8K]

$\sqrt x=5\\
x=25$

4 0

3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

5 0

3 years ago