Question

Whats the answer for 6b+7-2b=1+5b

Answer 1

$Solution,6b+7-2b=1+5b\quad :\quad b=6$

$Steps:$

$6b+7-2b=1+5b$

$\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b$

$\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7$

$\mathrm{Simplify}, 4b=5b-6$

$\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b$

$\mathrm{Simplify}, -b=-6$

$\mathrm{Divide\:both\:sides\:by\:}-1, \frac{-b}{-1}=\frac{-6}{-1}$

$\mathrm{Simplify}, b=6$

$\mathrm{The\:Correct\:Answer\:is\:b=6}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

Answer 2

Answer:

b=6

Step-by-step explanation:

We have the expression $6b+7-2b=1+5b$

We are to leave in one side of the expression all the terms that has b and in the other the terms that doesn't have b.

$6b+7-2b=1+5b\\6b-2b-5b=1-7$

We can apply common factor b in the left side, and resolve the subtraction in the right side.

$b(6-2-5)=-6\\b(-1)=-6$

Now divide both sides in (-1).

$b(-1)=-6\\\frac{b(-1)}{(-1)}=\frac{(-6)}{(-1)} \\b=6$

Then the answer of $6b+7-2b=1+5b$ is b=6.