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Lena [83]
3 years ago
8

A British company is sending you measurements for a table to build in your factory. The table top must be 50 cm × 75 cm. Your ma

chine calibrates in inches. Find the size of the table in inches. (1 cm = .39 in)
Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

<u>Answer:</u>

19.5 x 29.25 inches

<u>Step-by-step explanation:</u>

We are given that the top of the table, which we are to build in our factory must of the the dimension 50 cm x 75 cm.

Also, out machine is calibrated in inches. So to find the size of the table in the inches, we need to multiply the given dimensions of the table top with the scale (1 cm = 0.39 inches)

50 cm ---> 50 x 0.39 = 19.5 inches

75 cm ---> 78 x 0.39 = 29.25 inches

Therefore, the dimensions of the table in inches are 19.5 x 29.25 inches.

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yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

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3 years ago
What is the solution to the equation?
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Answer:

Hello,

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2

Step-by-step explanation:

\dfrac{2}{x} -\dfrac{x}{x+5} =\dfrac{10}{x^2+5x} \\\\we\ suppose\ x\neq 0\ and\ x\neq -5\\\\\text{Reducing to the same denominator}\\\dfrac{2(x+5)-x^2}{x(x+5)} =\dfrac{10}{x^2+5x} \\\\Simplify\ by\ x^2+5x\\\\2x+10-x^2=10\\\\-x^2+2x=0\\\\-x(x-2)=0\\\\roots\ are\ 2 \ and\ 0\ (to\ be\ excluded)\\\\Root=2\\

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