Answer:
-11/10 or -1.1
Step-by-step explanation:
To start, let's get rid of those pesky decimals by multiplying everything by 2. Then we get 9 + 20r = -13. Now, let's isolate the r by subtracting 9 from both sides to get 20r = -22. Finally, we need to divide everything by 20 to get r = -11/10 or -1.1.
The simplified form of 3 over 2x plus 5 + 21 over 8 x squared plus 26x plus 15 is <span>6 over the quantity 4 x plus 3.
</span>
The solution would
be like this for this specific problem:
( 3 /( 2x+5 )) + ( 21 / (8x^2 + 26x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (8x^2 + 20x + 6x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (4x(2x + 5) + 3(2x + 5))
= ( 3 /( 2x+5 )) + ( 21 /(2x + 5)(4x + 3)
= [ 3 (4x + 3) + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 9 + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 30 ] /(2x + 5)(4x + 3)
= 6(2x + 5) /(2x + 5)(4x + 3)
= 6 / (4x + 3)
<span>I am hoping that
this answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.</span>
Answer: A) The x-intercepts and the zeros are the same value.
Step-by-step explanation:
because when graphing the line goes through the origin and the origin is zero.
Hello...
Area is measured by the formula A=L*W (Area = Length X Width) We know the area is 38 1/4 and the width is 4 1/2. It is easiest to convert them to decimals and solve. 38 1/4 = 38.25 and 4 1/2= 4.5 . so, 38.25 = 4.5 * W
To solve for Width, we need to isolate it by getting 4.5 on the other side. To do this, we divide by 4.5 on both sides of the equals sign. this will give us W=8.5 or Width = 8 1/2 meters.
Given that we assume that all the bases of the triangles are parallel.
We can use AAA or Angle-Angle-Angle to prove that these triangles are similar.
Each parallel line creates the same angle when intersecting with the same side.
For example:
The bases of each triangle cross the left side of all the triangle.
Each angle made by the intersecting of the the parallel base and the side are the same.
Thus, each corresponding angle of all the triangles are congruent.
If these angles are congruent, then we have similar triangles.
