Please help with this problem for physics !

Chef tom works in a very busy restaurant. he cooks for 100's of people each night. why chef tom would use a copper pot instead o

Gala2k [10]

the copper pot heats up faster because it is a better conductor

6 0

3 years ago

Read 2 more answers

What is the density of a substance if 17 cm cubed has a mass of 35.7g

Arisa [49]

Density = (mass) / (volume)

Density = (35.7 g) / (17 cm³)

Density = 2.1 g/cm³

4 0

3 years ago

Match the physical properties on the left with their descriptions on the right. 1. luster ability to dissolve in another substan

Serjik [45]

Answer :

1) Luster → the shininess of a material

2) Freezing point → temperature at which a liquid becomes a solid

3) Viscosity → the measure of a substance's resistance to flow

4) Solubility → ability to dissolve in another substance

5) Ductility → able to be pulled into a wire

Explanation :

Luster : It is defined as the material which has the shining property.

Freezing point : It is the temperature at which the phase changes from liquid state to solid state at low temperature.

Viscosity : It measures the resistance of the liquids to flow .

Solubility : It is defined as the ability of a substance (solute) to dissolve into a liquid (solvent).

Ductility : It is defined as the ability of a metal into a thin wire without breaking.

7 0

4 years ago

How to detect an acid / base?

kirill115 [55]

ACID

Litmus Test- Blue litmus paper turns red in acidic medium.
pH test- Dip a pH paper into the solution. And check for the corresponding values on the pH scale for the colours that appear. If the value is below 7, its acidic

BASE

Litmus Test- red litmus paper turns blue in basic medium.
pH test - Dip a pH paper into the solution. And check for the corresponding values on the pH scale for the colours that appear,if it's above 7, it's basic.

3 0

4 years ago

He angular position of a swinging door is described by θ = 5.00 + 10.0 t + 2.00 t2 [rad]. (a) determine the angular position, an

Inessa05 [86]

(a) The angular position of the door is described by
$\theta(t)=5+10t+2t^2 [rad]$

The angular velocity is given by the derivative of the angular position:
$\omega(t)=10+4t [rad/s]$

While the angular acceleration is given by the derivative of the angular velocity:
$\alpha(t)=4 [rad/s^2]$

We want to find the values of these quantities at time t=3.00 s, so we must substitute t=3.00 s into the expressions for $\theta, \omega, \alpha$ :
$\theta(3.00 s)=5+(10)(3.00 s)+2(3.00s)^2 = 53 rad$
$\omega(3.00 s)=10+4(3.00s)=22 rad/s$
$\alpha(3.00s)=4 rad/s^2$

(b) The door starts from rest, so its initial angular velocity is $\omega_i=0 rad/s$ , and it reaches a final angular velocity of $\omega_f=0.750 rad/s$ with an angular acceleration of $\alpha=0.560 rad/s^2$ . We can find the angular distance covered by the door by using the following relationship:
$2 \alpha \theta = \omega_f^2 - \omega_i^2$
from which we find
$\theta= \frac{\omega_f^2}{2 \alpha}= \frac{(0.750 rad/s)^2}{2 \cdot 0.560 rad/s^2} =0.502 rad$

6 0

3 years ago