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2 years ago

300 g2 divide by 0.0005 g in scientific notation

Physics

1 answer:

lubasha [3.4K]2 years ago

3 0

We are given the problem:

300 g divide by 0.0005 g

So simply divide:

300 g / 0.0005 g = 600,000

To write it in scientific notation, we need to move the decimal place 5 places to the left:

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80N force ;

lutik1710 [3]

The power of the engine is 320 W.

<u>Explanation:</u>

Power may be defined as the rate of doing work (or) work done per unit time. One unit of energy is used to do the one unit of work.

Power = Work done / Time taken

Given, Force = 80 N, height = 5 m , final velocity = 4 m/s

To calculate the power, we must know the time taken.

To find the time, use the distance and speed formula which is given by

Time = Distance / speed

Here distance = 5 m and speed = 4 m/s

Time = 5 / 4 = 1.25 s.

Now, Power = work done / time

= (F * d) / t = (80 * 5) / 1.25

Power = 320 W.

The standard unit of power is watt (W) which is joule per second.

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. A 2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) What is the block’s accelerat

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Answer:

a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N

Explanation:

a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry

sin 30 = Wx / W

cos 30 = Wy / W

Wx = W sin30

Wy = W cos 30

Let's write the equations on each axis

X axis

Wx = ma

Y Axis

N- Wy = 0

N = Wy = mg cos 30

N = 2.0 9.8 cos 30

N = 16.97 N

We calculate the acceleration

a = Wx / m

a = mg sin 30 / m

a = g sin 30

a =9.8 sin 30

a = 4.9 m / s²

b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component

F -Wx = 0

F = Wx

F = m g sin 30

F = 2.0 9.8 sin 30

F = 9.8 N

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Answer:

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Read 2 more answers

You build a grandfather clock, whose timing is based on a pendulum. You measure its period to be 2s on Earth. You then travel wi

Elenna [48]

Answer:

$\frac{g_{2}}{g_{1}} = \frac{1}{4}$

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$T = 2\pi\cdot \sqrt{\frac{l}{g} }$

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$g$ - Gravity constant, in $\frac{m}{s^{2}}$ .

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$T_{1}^{2}\cdot g_{1} = T_{2}^{2}\cdot g_{2}$

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