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3 years ago

300 g2 divide by 0.0005 g in scientific notation

Physics

1 answer:

lubasha [3.4K]3 years ago

3 0

We are given the problem:

300 g divide by 0.0005 g

So simply divide:

300 g / 0.0005 g = 600,000

To write it in scientific notation, we need to move the decimal place 5 places to the left:

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A projectile is fired with a velocity of 320 ms at an angle of 30 degree to a horizontal.1 Find the time to reach the maximum he

dedylja [7]

(a) The time taken for the projectile to reach the maximum height is 32.65 s.

(b) The horizontal range of the projectile is 9,049.1 m.

The given parameters:

Initial velocity of the projectile, u = 320 m/s
Angle of projection, = 30 degrees

The time taken for the projectile to reach the maximum height is calculated as follows;

$v_f = u- gt\\\\0 = 320 - 9.8t\\\\9.8t = 320\\\\t = \frac{320}{9.8} \\\\t = 32.65 \ s$

The horizontal range of the projectile is calculated as follows;

$R = \frac{u^2 sin(2\theta)}{g} \\\\R = \frac{320^2 \times sin(2\times 30)}{9.8} \\\\R = 9,049.1 \ m$

Learn more about horizontal range here: brainly.com/question/12870645

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3 years ago

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elena55 [62]

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3 years ago

A particle's position along the x-axis is described by: x(t)=A t + B t2

ki77a [65]

Answer:

a)V = 25.1 m/s

b)V = 4.226 m/s

Explanation:

Given that

x(t)=A t + B t²

A = -4.3 m/s

B = 4.9 m/s²

x(t)= - 4.3 t +4.9 t²

The velocity of the particle is given as

$V=\dfrac{dx}{dt}$

V=-4.3 + 4.9 x 2 t

V= - 4.3 + 9.8 t m/s

Velocity at point t= 3 s

V= - 4. 3 + 9.8 x 3 m/s

V= - 4.3 + 29 .4 m/s

V = 25.1 m/s

At origin :

x= 0 m

0 = - 4.3 t +4.9 t²

0 = - 4.3 + 4.9 t

$t=\dfrac{4.3}{4.9}\ s$

t=0.87 s

The velocity at t= 0.87 s

V= - 4.3 + 9.8 t m/s

V= - 4. 3 + 9.8 x 0.87 m/s

V= - 4.3 + 8.526 m/s

V = 4.226 m/s

a)V = 25.1 m/s

b)V = 4.226 m/s

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3 years ago

A bike travels at a constant speed of 3.1 m/s for 6 s. how far does it go?

IgorC [24]

Ah for this problem you are thinking quite a bit hard on. The problem is actually simpler than it looks. The problem states that a bike travels at a constant speed of 3.1 m/s for 6 s and asks how far will it go?. To figure this out you simply need to take 3.1 times 6 s because every second the bike travels 3.1 m. So the answer to this problem would be 18.6 m

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4 years ago

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe

iris [78.8K]

Answer:

Explanation:

1. $V_{x}$ = $V_{0}$ * cos $\alpha$ ⇒ 16*cos32 ≈ 13.6 m/s (13.56)

2. $V_{y}$ = $V_{0}$ * sin $\alpha$ ⇒ 16* sin32 ≈ 9.4 m/s

3. $y_{max}$ = $\frac{v_{0}^2*sin^2\alpha}{2g}$ = $\frac{16^2*sin^232}{2*9.8}$ (the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)

$y_{max}$ ≈ 3.6677+1.5 ≈ 5.2m

4. $x_{max}$ = $\frac{v_{0}^2*sin(2\alpha)}{g}$ = $\frac{16^2*sin(2*32)}{9.8}$ ≈ 23.5m (23.47)

5. -

answer 4 could be wrong, not certain about that one and i don't know 5

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3 years ago