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Elden [556K]
3 years ago
14

Solve the simultaneous equation x+y/4=1/2 and x-3y/3=2

Mathematics
2 answers:
baherus [9]3 years ago
4 0

Answer:

one solution (9/2 ; -1/2)

Step-by-step explanation:

hello :

the system is :

x+y/4=1/2

x-3y/3=2

means : 2(x+y)=4

             x-3y = 6

so : x+y = 4 ...(*)

     x-3y =6  ....(**)

by (*) : x = 4-y  and by (**) : x = 6+3y

so : 6+3y = 4-y

4y =-2    so    y = -1/2

x = 4 - (-1/2) = 9/2

Feliz [49]3 years ago
3 0

Answer:

x+y/4 = 1/2

x-3y/3 = 2

move variables to one side:

multiply the first equation by 4 to get: x+y =2

and the second equation by 3 to get: x-3y =6

then subtract the equations to cancel out x:

 x+y = 2

- x-3y = 6

then u get

y--3y = 2-6

4y = -4

y=-1

substitute to solve for x:

x-1 / 4 =1/2

x-1 = 2

x=3

check:

3+-1

2/4= 1/2

correct!!!

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