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Nostrana [21]
3 years ago
13

Line AB contains points A (0, 0) and B (2, 2). Line CD contains points C (3, 1) and D (5, 3). Lines AB and CD are

Mathematics
2 answers:
polet [3.4K]3 years ago
5 0
It is parallel because if you graph the points on graph paper they come out parallel.
Schach [20]3 years ago
4 0

Answer:

Option A is correct.

Lines AB and CD are parallel.

Step-by-step explanation:

Parallel lines: They have the same slope and will never intersects.

Perpendicular lines : The slope of the perpendicular are negative reciprocal to each other.

As per the statement:

Line AB contains points A (0, 0) and B (2, 2).

Slope the two points is given by:

\text{Slope} = \frac{y_2-y_1}{x_2-x_1}

then;

\text{Slope AB} = \frac{2-0}{2-0}=\frac{2}{2}=1

Similarly for:

Line CD contains points C (3, 1) and D (5, 3)

then;

\text{Slope CD} = \frac{3-1}{5-3}=\frac{2}{2}=1

Since, the slope of AB = Slope of CD

then by definition:

⇒Lines AB and CD are parallel.

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Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe
kherson [118]

Answer:

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}  

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

We don't have a prior estimation for the proportion \hat p so we can use 0.5 as an approximation for this case  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
I need answers please​
Semmy [17]
4. 0.76
5. 0.18
8. 4.48
9. 0.08
12. 3.08
13. 0.45

:)
4 0
3 years ago
The following table shows values from a linear function. What is the
Naddik [55]

Answer:

9

Step-by-step explanation:

The equation graphed from these points is y=3x+9, therefore the y-intercept is 9.

4 0
3 years ago
Can someone help me with this and have it step by step please
Sladkaya [172]

Answer:

should also be 40

Step-by-step explanation:

the measure of angle 1 is equivelent to angle two, since they both lie ont he same line.

8 0
3 years ago
Pls help me I will give brainlyiest
storchak [24]

Answer:

57.72 in^2

Step-by-step explanation:

Question 1. Shapes are triangle, semi-circle, and rectangle.

Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.

Question 3.

Rectangle's area:<u>48 in^2</u>

Triangles area:8*4/2=  <u>16 in^2</u>

Circle Area: pi*r^2/2(since its a semi-circle)

3.14*2^2=3.14*4=12.56/2=<u>6.28 in^2</u>

Question 4.

16-6.28=9.72

9.72+48=57.72 in^2

5 0
3 years ago
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