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Veronika [31]
4 years ago
5

The difference of the same side angles of two parallel lines is 35°. Find all angles

Mathematics
1 answer:
Pavel [41]4 years ago
3 0
<h3>Answer:</h3>

All acute angles are 72.5°; all obtuse angles are 107.5°.

<h3>Explanation:</h3>

Angles on the same side of a transversal cutting parallel lines have measures that total 180°. If o and a represent the measures of the obtuse and acute angles, respectively, then we have ...

... o + a = 180

... o - a = 35

Adding these two equations gives ...

... 2o = 215

... 215/2 = o = 107.5 . . . . degrees

Then the other angle is ...

... a = 107.5 - 35 = 72.5 . . . . degrees

_____

All corresponding angles have the same measures. All vertical angles have the same measures. So the 8 angles that arise from the intersection of the transversal with these two parallel lines will have one or the other of these two measures.

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1 ) Solve for x: -5x-1247 2) Solve the following quadratic equation by
velikii [3]

Two solutions were found :

x = 8

x = -4

Rearrange: x^2-4*x-(32)=0

Step by step solution :

1.1     Factoring  x2-4x-32

The first term is,  x2  its coefficient is  1 .

The middle term is,  -4x  its coefficient is  -4 .

The last term, "the constant", is  -32

Step-1 : Multiply the coefficient of the first term by the constant   1 • -32 = -32

Step-2 : Find two factors of  -32  whose sum equals the coefficient of the middle term, which is   -4 .

     -32    +    1    =    -31

     -16    +    2    =    -14

     -8    +    4    =    -4    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -8  and  4

                    x2 - 8x + 4x - 32

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-8)

             Add up the last 2 terms, pulling out common factors :

                   4 • (x-8)

Step-5 : Add up the four terms of step 4 :

                   (x+4)  •  (x-8)

            Which is the desired factorization

Equation at the end of step  1  :

 (x + 4) • (x - 8)  = 0

Step  2  :

Theory - Roots of a product :

2.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2      Solve  :    x+4 = 0

Subtract  4  from both sides of the equation :

                     x = -4

Solving a Single Variable Equation :

2.3      Solve  :    x-8 = 0

Add  8  to both sides of the equation :

                     x = 8

Supplement : Solving Quadratic Equation Directly

Solving    x2-4x-32  = 0   directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

3.1      Find the Vertex of   y = x2-4x-32

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is   2.0000  

Plugging into the parabola formula   2.0000  for  x  we can calculate the  y -coordinate :

 y = 1.0 * 2.00 * 2.00 - 4.0 * 2.00 - 32.0

or   y = -36.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = x2-4x-32

Axis of Symmetry (dashed)  {x}={ 2.00}

Vertex at  {x,y} = { 2.00,-36.00}

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-4.00, 0.00}

Root 2 at  {x,y} = { 8.00, 0.00}

Solve Quadratic Equation by Completing The Square

3.2     Solving   x2-4x-32 = 0 by Completing The Square .

Add  32  to both side of the equation :

  x2-4x = 32

Now the clever bit: Take the coefficient of  x , which is  4 , divide by two, giving  2 , and finally square it giving  4

Add  4  to both sides of the equation :

 On the right hand side we have :

  32  +  4    or,  (32/1)+(4/1)

 The common denominator of the two fractions is  1   Adding  (32/1)+(4/1)  gives  36/1

 So adding to both sides we finally get :

  x2-4x+4 = 36

Adding  4  has completed the left hand side into a perfect square :

  x2-4x+4  =

  (x-2) • (x-2)  =

 (x-2)2

Things which are equal to the same thing are also equal to one another. Since

  x2-4x+4 = 36 and

  x2-4x+4 = (x-2)2

then, according to the law of transitivity,

  (x-2)2 = 36

We'll refer to this Equation as  Eq. #3.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x-2)2   is

  (x-2)2/2 =

 (x-2)1 =

  x-2

Now, applying the Square Root Principle to  Eq. #3.2.1  we get:

  x-2 = √ 36

Add  2  to both sides to obtain:

  x = 2 + √ 36

Since a square root has two values, one positive and the other negative

  x2 - 4x - 32 = 0

  has two solutions:

 x = 2 + √ 36

  or

 x = 2 - √ 36

Solve Quadratic Equation using the Quadratic Formula

3.3     Solving    x2-4x-32 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     1

                     B   =    -4

                     C   =  -32

Accordingly,  B2  -  4AC   =

                    16 - (-128) =

                    144

Applying the quadratic formula :

              4 ± √ 144

  x  =    —————

                   2

Can  √ 144 be simplified ?

Yes!   The prime factorization of  144   is

  2•2•2•2•3•3

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 144   =  √ 2•2•2•2•3•3   =2•2•3•√ 1   =

               ±  12 • √ 1   =

               ±  12

So now we are looking at:

          x  =  ( 4 ± 12) / 2

Two real solutions:

x =(4+√144)/2=2+6= 8.000

or:

x =(4-√144)/2=2-6= -4.000

Two solutions were found :

x = 8

x = -4

THIS IS FOR x2-4x=32. i dont have enough space to show work for the 1st one im so sorryy! but the answer is :

     -1 • (5x + 1247)

6 0
3 years ago
Draw a number line and mark all described points on it. Numbers that are both larger than –2 and smaller than 3.
vfiekz [6]

Answer:

The numbers larger than -2 and smaller than 3 are -1,0,1,2.

Step-by-step explanation:

4 0
4 years ago
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4(x+8)+5(x-3) simplified
dolphi86 [110]

Answer:

9x+17

Brainliest pls

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3 years ago
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Triangle ABC contains side lengths b=3 inches and c= 5 inches in two or more sentences describe whether or not it is possible fo
Scrat [10]

Answer:

Since sine of all angles are always less than one, this shows there is no possible way to have an angle C. Thus it is impossible to have a triangle ABC with the given properties of side lengths b=3 inches and c= 5 inches to have angle B =45 degrees.

Step-by-step explanation:

In the attached  drawing, each of the tic-marks are equal and

represent 1 inch each.  The angle B has measure 45.  We can

see by the arc that the line AC, which equals 3 inches, is

not long enough to reach the slanted side of the 45 angle.

Therefore triangle ABC is not possible.  We can also show

by the law of sines that no triangle ABC with the given

properties in possible.

5 0
3 years ago
3. Write and solve an equation to
Anna71 [15]

Answer:

x = 27

Step-by-step explanation:

Given

The attached figure

Required

Solve for x

3x and 45 are supplementary angles

So:

3x + 45 = 180

3x =- 45 + 180

3x =135

Solve for x

x = 135/5

x = 27

8 0
3 years ago
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