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Veronika [31]
3 years ago
5

The difference of the same side angles of two parallel lines is 35°. Find all angles

Mathematics
1 answer:
Pavel [41]3 years ago
3 0
<h3>Answer:</h3>

All acute angles are 72.5°; all obtuse angles are 107.5°.

<h3>Explanation:</h3>

Angles on the same side of a transversal cutting parallel lines have measures that total 180°. If o and a represent the measures of the obtuse and acute angles, respectively, then we have ...

... o + a = 180

... o - a = 35

Adding these two equations gives ...

... 2o = 215

... 215/2 = o = 107.5 . . . . degrees

Then the other angle is ...

... a = 107.5 - 35 = 72.5 . . . . degrees

_____

All corresponding angles have the same measures. All vertical angles have the same measures. So the 8 angles that arise from the intersection of the transversal with these two parallel lines will have one or the other of these two measures.

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drek231 [11]
Using the Pythagorean Theorem,
radius^2 = 40^2 + 9^2
radius^2 = 1,600 + 81
radius^2 = 1,681
radius = 41


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3 years ago
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If (x) = x+8 and g(x) = -4x-3, find (f+ g)(x).
Ede4ka [16]

Answer:

Answer=B

(f+g)(x)=-3x-5

Step-by-step explanation:

f(x)=x+8.

g(x)=-4x-3.

(f+g)(x) means f(x)+g(x),So

(x+8)+(-4x-3)

(add all same terms together)

=(x+(-4x))+(8+(-3))

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so,

(f+g)(x)=-3x+5

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3 years ago
A company hauls its 1 cubic foot boxes in the truck as shown.
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Step-by-step explanation:

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4 0
3 years ago
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Find the least common denominator for these two rational expressions 7/n^2 -8/7n
lianna [129]

Answer:

7n²

Step-by-step explanation:

7/n² - 8/7n

Least common multiple will be the least common denominator

L.C.M = 7n²

Dividing the L.C.M by denominators and multiplying with numerators;

((7×7) - (n×8))/7n²

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3 years ago
For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

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Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

3 0
3 years ago
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