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Colt1911 [192]
4 years ago
15

Rachel's average score after 6 tests is 83. If Rachel earns a score of 97 on the 7th test, what is her new average?

Mathematics
1 answer:
vredina [299]4 years ago
8 0
We know that

[<span>Rachel's new average]=[6*83+97]/7-----> [498+97]/7----> 595/7----> 85

the answer is
</span><span>Rachel's new average score is 85</span>
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Answer:

x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4

Step-by-step explanation:

Solve for x:

x - 1 - 2/x = 3 x + 2

Bring x - 1 - 2/x together using the common denominator x:

(x^2 - x - 2)/x = 3 x + 2

Multiply both sides by x:

x^2 - x - 2 = x (3 x + 2)

Expand out terms of the right hand side:

x^2 - x - 2 = 3 x^2 + 2 x

Subtract 3 x^2 + 2 x from both sides:

-2 x^2 - 3 x - 2 = 0

Divide both sides by -2:

x^2 + (3 x)/2 + 1 = 0

Subtract 1 from both sides:

x^2 + (3 x)/2 = -1

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = -7/16

Write the left hand side as a square:

(x + 3/4)^2 = -7/16

Take the square root of both sides:

x + 3/4 = (i sqrt(7))/4 or x + 3/4 = -(i sqrt(7))/4

Subtract 3/4 from both sides:

x = (i sqrt(7))/4 - 3/4 or x + 3/4 = -(i sqrt(7))/4

Subtract 3/4 from both sides:

Answer:  x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4

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Answer:

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Step-by-step explanation:

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Rzqust [24]

Answer:

Step-by-step explanation:

Remark

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