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3 years ago

How much would $200 invested at 6% interest compounded annually be

Mathematics

1 answer:

AleksAgata [21]3 years ago

3 0

Answer:

A= P(1 + r)^n

where,

A= final balance

P= initial quantity

n= number of compounding periods

r= percentage interest rate

So,

P= $200

n= 6 years

r= 6%= 0.06

=$200(1 + 0.06)^6

=$283.70

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Step-by-step explanation:

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4 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

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The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

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The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

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=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

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$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

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=> $P_o = \frac{600}{180} * 168587.7$

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4 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

how large is the acceleration of a 60 kg runner if the friction between her shoes and the pavement is 500 n?

melomori [17]

The force of friction is given in the scenario:

Force = 500 Newton

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To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:

$F=m\times a$

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Plugging the value of variables we get:

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Solving for 'a' (acceleration) we get:

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So the acceleration of the runner is 8.33 meters/ second squared.

8 0

4 years ago