For the first one, you're answer would be AC. since C is also a right angle, and angle A is hypnotenuse to C
Step 1
State the formula for the probability of an event
![Pr(event)=\frac{required\text{ number of events }}{Total\text{ number of events}}](https://tex.z-dn.net/?f=Pr%28event%29%3D%5Cfrac%7Brequired%5Ctext%7B%20number%20of%20events%20%7D%7D%7BTotal%5Ctext%7B%20number%20of%20events%7D%7D)
The required number of event= The students with 2 or more pets= 15+7+3+2+0 = 27
Total number of events=4+11+15+7+3+2+0=42
Step 2
Estimate the probability that a randomly selected student from this class has 2 or more pets.
![Pr(Students\text{ with }2\text{ pets or more})\frac{27}{42}\approx0.64](https://tex.z-dn.net/?f=Pr%28Students%5Ctext%7B%20with%20%7D2%5Ctext%7B%20pets%20or%20more%7D%29%5Cfrac%7B27%7D%7B42%7D%5Capprox0.64)
Answer; Option C 27/42 or approximately 0.64
Answer:
x = 5, y =2
Step-by-step explanation:
I guess the question is saying x+y = 7 and 3x-2y = 11?
then there are multiple ways but
I will multiply the first one by 2 so 2x+2y = 14
you add the equations to get 5x = 25 so x = 5 plug x into the first equation you get y = 2
if that isn't what the question means just comment and I'll change it
Answer:
Step-by-step explanation:
Add the -5.57 to both sides then divide it by 2 which is -0.91
Answer:
b = -8
Step-by-step explanation:
crossmultiply