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3 years ago

8

Math help!!!? How do I solve this problem? Can anyone explain?

1 answer:

garik1379 [7]3 years ago

3 0

First you find what fits the qualifications of the function.
Part 1: f(0) fits with x<= 1, so you simply plug in 0 for that function.
(0)^2 = 1

Part 2: f(x) = 1
That means there is a horizontal straight line intersecting (0,1)

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5.65 times 3.4 estimate

lidiya [134]

We can round 5.65 up to 6 and 3.4 down to 3.
3 * 6 = 18
now let's see how close our estimate is to the real answer
5.65 * 3.4 = 19.21
Our answer was pretty close to the real answer!

Hope I helped!
~ Zoe

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4 years ago

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Amanda, Barney, Colin, Diana, and Erika are going to a baseball game. They have a total budget of $100.00 to spend. Each game ti

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Answer:

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3 years ago

Is (0, -1) a solution of -101 + 4y > -4?

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Answer:

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Step-by-step explanation:

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3 years ago

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73

faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]

Therefore,

CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})$

Thus,

Lower limit of CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}})$

or

Lower limit of CI = $(98.3 - \frac{2.62\times0.73}{\sqrt{103}})$

or

Lower limit of CI = 98.11

and,

Upper limit of CI = $(Mean + \frac{t\times\sigma}{\sqrt{n}})$

or

Upper limit of CI = $(98.3 + \frac{2.62\times0.73}{\sqrt{103}})$

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F

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3 years ago

The midpoint of EF is M(4,10) one endpoint is E(2,6). Find the coordinates of the other endpoint F

Vera_Pavlovna [14]

2+a / 2 = 4 and b+6 /2 = 10

2+a=8. and. b+6 = 20
a=6. and. b=14

(a,b) , the other endpoint, is thus (6,14)

3 0

3 years ago