We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
where
A = total amount in the account at the end of t years
r represents the interest rate
n represents the periodic interval at which it was compounded
p represents the principal or initial amount deposited
From the information given,
P = 11260
t = 6
r = 7.5/100 = 0.075
n = 52(Assuming the number of weeks in a year is 52 and it would be compounded 52 times in a year)
Thus, we have
A = 11260(1 + 0.075/52)^52*6
A = 11260(1 + 0.075/52)^312
A = 17653.5
Idk what deviation set is but im guessing B because each term went up by 1
A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are:
=-1,+1,-2,+2,-11,+11,-22+22.
b)
one zero of the funtion can be: x=-1 ⇒y=0
(-1,0)c)
other zero of the funtion is: x=-2 ⇒y=0
(-2,0)d)
if x=0 then y=22
(0,22)
e) In the file is the graph.
Let's see what the options look like when we multiply the expressions in brackets:
(first, i multiply both parts of the second bracked by the first part of the first bracket, and then the same with the second part of the first bracket:
<span>(1) (3x - 3)(x - 2))
3x2 +6x -3x +6// this is not correct
(2) (3x + 3)(x - 2) </span>
3x2-6x+3x-6//this is not correct
(3)
3(x + 1)(x - 2)
3(x2-2x+x-2)//simplifying:
3(x2-x-2)//multiplying:
3x2-3x-6)
- so this is not correct either
(4) 3(x - 1)(x - 2)
3(x2-2x - x + 2)
3(x2-3x +2)
3x2-9x +6 - well, here is our winner!
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62.
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.
To find the missing distance in the right triangle. You have to use the Pythagorean Theorem. I set it up and solve it below.
a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)
