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erica [24]
3 years ago
11

In school we're learning about square roots. We have a quiz Monday on square roots 1-20 and we have 2 minutes to go it I need a

trick to make learning them easier and quicker please
Mathematics
2 answers:
Fantom [35]3 years ago
5 0
Are you learning about the simple square roots, as in square root of 36 for example? If so.. the best "trick" that I can think of to make it easier is if you know your multiplication pretty well, then it should be helpful.

Square root of 36 is 6 because 6 times 6 equals 36.
Square root of 49 is 7 because 7 times 7 equals 49.
Square root of 81 is 9 because 9 times 9 equals 81.
And so on.

amm18123 years ago
3 0
Make a song with the numbers I did this in 4th grade.
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Write an algebraic equation to represent the problem:
Alex73 [517]

Answer:

20%

Step-by-step explanation:

That’s because 3/15 = 1/5, which is 20%

8 0
2 years ago
Read 2 more answers
Area of a trapezium is 31.5cm. If the parallel sides are of lengths 7.3cm and 5.3cm. Calculate the perpendicular distance betwee
Anna11 [10]

Answer:

5cm

Step-by-step explanation:

Given area of trapezium = 31.5 sq. cm

Length of parallel sides = 7.3cm and 5.3cm

Formula to calculate area of trapezium is

1/2*(sum of parallel sides)*perpendicular distance between parallel sides

sum of parallel sides =  (7.3 + 5.3) = 12.6cm

substituting value of area given and sum of parallel sides we have

31.5 = 1/2* 12.6 * perpendicular distance between parallel sides

(31.5 * 2)/12.6 = perpendicular distance between parallel sides

perpendicular distance between parallel sides = 63/12.6 = 5

Therefore perpendicular distance between parallel sides for given trapezium is 5cm.

5 0
3 years ago
Math Glass Worksheet (A lot of points)
Ray Of Light [21]

Answer:

<em>You can chose 3 in 5</em><em> :o</em>

Step-by-step explanation:

<em></em>

3 0
3 years ago
Choices;<br> a) 21.8°<br> b) 35.2°<br> c) 45.1°
kifflom [539]

Answer:

\displaystyle a) \: {x}^{ \circ}  =  21.8 ^{ \circ}

Step-by-step explanation:

we are given opposite and adjacent

we want to figure out x°

remember that,

\displaystyle \: \tan( \theta)  =  \frac{opp}{adj}

where our opp is 5 and adj is 12.5

let \theta be x°

so

\displaystyle \: \tan(  {x}^{ \circ} )  =  \frac{5}{12.5}

\displaystyle \: {x}^{ \circ}  =  \arctan \left( \frac{5}{12.5}  \right)

by using calculator

\displaystyle \: {x}^{ \circ}  =  21.8

hence,

our answer is a

6 0
3 years ago
Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Kamila [148]

Answer:

17. z=39/sin45=78/\sqrt{2}

    y=39/tan60=39/\sqrt{3}

    x=y/sin60=78/\sqrt{3}

19. x=6\sqrt{3}/tan60=6

    y=2x=12

    z=\sqrt{2}y=12\sqrt{2}

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=78/\sqrt{2}

then: tan60=39/y

so:    y=39/tan60=39/\sqrt{3}

last:  sin60=y/x

so:    x=y/sin60=78/\sqrt{3}

19.

because: tan60=6\sqrt{3}/x

so:            x=6\sqrt{3}/tan60=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=\sqrt{2}y=12\sqrt{2}

   

4 0
2 years ago
Read 2 more answers
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