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3 years ago

What is 1 divided by 998,001 to 9 decimal places?

Mathematics

1 answer:

Otrada [13]3 years ago

7 0

Trick question? :P

1/998,001 should be:

0.000001002 or

1.00200300*10^-6

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2 years ago

A man's shoe size is related to his foot length and can be modeled by the equation s = 1.7f - 7.2, where s is shoe size and f is

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Step-by-step explanation:

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3 years ago

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A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

$P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.$

Then

$P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}$

$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

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3 years ago

Evaluate 10x2y-2 for x = -1 and y = -2.

Rzqust [24]

Answer:

Step-by-step explanation:

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3 years ago

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A soccer team estimates that they will score on 77% of the corner kicks. In next week's game, the team hopes to kick 1414 corn

andrezito [222]

Answer:

18.66521%

Step-by-step explanation:

It seems all of the numbers are duplicated, the correct number should be 7%, 14 corner kicks, and 2 opportunities.

The team has 7%(x=0.07) chance to score so that means the chance to not scoring will be: y= 1-x = 100%-7%= 93%. There are 14 opportunities and we want to know the probability to get exactly 2 scores. The calculation will be:

P(x=2)= 2C14 * x^2 * y^12

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