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sergij07 [2.7K]
3 years ago
10

What is the least common multiple for 6 and 21?

Mathematics
1 answer:
Crank3 years ago
5 0
3 is the least common multiple for 6 and 21
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What is the order of this matrix.
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Answer:

the order of the matrix is 5 x 3

5 rows and 3 columns

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Please help me with my math hw
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<span> <span> </span><span><span> <span> Selling Price </span> <span> Cost </span>          <span> Profit </span> <span>       Mark up </span> </span> <span> <span>          
    75.99 </span> <span>          61.00 </span> <span>        14.99 </span> <span>          0.25
</span></span><span><span>    29.95 </span> <span>          23.75 </span> <span>          6.20 </span> <span>          0.26</span></span><span><span>   
    19.25 </span> <span>          15.00 </span> <span>          4.25 </span> <span>          0.28</span></span><span><span>            
      1.50 </span><span>            1.19 </span> <span>          0.31 </span> <span>          0.26</span></span><span><span>     
    54.99 </span> <span>          44.55 </span> <span>        10.44 </span> <span>          0.23</span></span><span><span>          
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Profit = Selling price - Cost
Mark up = Profit / cost </span></span></span></span>
4 0
3 years ago
Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.
hram777 [196]

The center of mass is mathematically given as

\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \  \ \  x \in(0,1)$ \\\end

We calculate the total mass of the system.

\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}

Step 03: Calculate the moment of the system.

\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}

we calculate the center of mass.

\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

Read more about the center of mass.

brainly.com/question/27549055

#SPJ1

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Step-by-step explanation:

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